Answer:
- a(x) = 20 + 0.60x
- domain [0, 50]; range [20, 50]
- maybe
Step-by-step explanation:
a) If x liters are removed from a container with a volume of 50 L, the amount remaining in the container is (50 -x) liters. Of that amount, 40% is acid, so the acid in the container before any more is added will be ...
0.40 × (50 -x)
The x liters are replaced with 100% acid, so the amount of acid that was added to the container is ...
1.00 × (x)
Then after the remove/replace operation, the total amount of acid in the container is ...
a(x) = 0.40(50 -x) +1.00(x)
a(x) = 20 +0.60x . . . . . liters of acid in the final mixture
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b) The quantity removed cannot be less than zero, nor can it be more than 50 liters. The useful domain of the function is 0 ≤ x ≤ 50. (liters)
The associated range is 20 ≤ a ≤ 50. (liters)
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c) As we found in part b, the amount of acid in the final mixture may range from 20 liters to 50 liters. So, the percentage of acid in the final mix will range from 20/50 = 40% to 50/50 = 100%. The mixture could be 50% acid, but is not necessarily.
How many sixths are in 1/2?
3
Step-by-step explanation:
i did it
Y=7 becuase 5+2 IM ASSUMING is 7 so the value of y=7
2^(3-9)-11 =
1 step: subtract the 3 and 9 to get 6
(3-9)=6
2 step: multiply 2 to its self 6 times and
you should get 64
2*2=4*2=8*2=16*2=32*2=64
3 step: subtract 11 by 64 to get 53
64-11=53
hope I help if so hit the brainliest thanks
Answer:
7.07107cm
Step-by-step explanation:
d= 
