Answer: 9.7 days
Explanation:
Applying Kepler's 3rd law, we can write the following proportion:
(Tm)² / (dem)³ = (Tsat)² / (dem/2)³
(As the satellite is placed in an orbit halfway between Erth's center and the moon's orbit).
Simplifyng common terms, and solving for Tsat, we have:
Tsat = √((27.3)²/8) = 9.7 days
1.1111111111
Explanation:
v=s/t
t=8:30-7:00=1:30
convert to second=5400second
s=60km covert to meter=6000
6000/5400=1.11111111
answer: transverse and longitudinal
