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Artist 52 [7]
4 years ago
14

What is the index of refraction?

Physics
2 answers:
laiz [17]4 years ago
6 0

Answer:

a. the ratio of the speed of light in a vacuum to the speed of light in the material it is passing though    

Explanation:

When a light ray enters from one medium to another, it bends. This is because the speed of light decreases as it enters a medium having more optical density. The speed of light is maximum in vacuum.

The refractive index determines the optical density of a medium. It is the ratio of the speed of light in the vacuum (c) to the speed of light in the material it is passing through (v).

\mu=\frac{c}{v}

quester [9]4 years ago
4 0

Answer:

The correct answer is a. the ratio of the speed of light in a vacuum to the speed of light in the material it is passing though

Explanation:

I took the test

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Two identical small charged spheres are a certain distance apart, and each initially experiences an electrostatic force of magni
sweet-ann [11.9K]

Answer:

d) 1/4 F

Explanation:

The magnitude of electrostatic force between stationary charges is described by Coulomb's law. This law states that this force is proportional to the magnitudes of the charges:

F\propto q_1q_2

When each of the spheres has lost half its initial charge, we have:

q_1'=\frac{q_1}{2}\\q_2'=\frac{q_2}{2}

So, the new electrostatic force is:

F'\propto q_1'q_2'\\F'\propto \frac{q_1}{2}\frac{q_2}{2}\\F'\propto \frac{q_1q_2}{4}\\F'\propto\frac{1}{4}F

5 0
4 years ago
Conductors an insulators
sladkih [1.3K]

Conductors transfer energy (metal is a good one) and insulators stop the transfer of energy (such as rubber or plastic). Sorry if that is wrong, but I hope it helps!

6 0
3 years ago
AreaAgNO3 + ___Response area_Li →_____Response areaLiNO3 +____Response areaAg
Solnce55 [7]

Answer:

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Explanation:

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6 0
3 years ago
Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 2 sin2(t), y = 2 cos2(
Tanya [424]

The distance traveled by the particle at the given time interval is 0.28 m.

<h3>Position of the particle at time, t = 0</h3>

The position of the particle at the given time is calculated as follows;

x = 2 sin2(t)

y = 2 cos2(t)

x(0) = 2 sin2(0) = 0

y(0) = 2 cos2(0) = 2(1) = 2

<h3>Position of the particle at time, t = 4</h3>

x = 2 sin2(t)

y = 2 cos2(t)

x(4) = 2 sin2(4) = 0.28

y(4) = 2 cos2(4) = 2(1) = 1.98

<h3>Distance traveled by the particle at the given time interval</h3>

d = √[(x₄ - x₀)² + (y₄ - y₀)²]

d =  √[(0.28 - 0)² + (1.98 - 2)²]

d = 0.28 m

Thus, the distance traveled by the particle at the given time interval is 0.28 m.

Learn more about distance here: brainly.com/question/23848540

#SPJ1

7 0
2 years ago
One positve and one negative charhe jave a force of -5. 00 N between them. If the force changed to -170 N , by what factor did t
stepladder [879]

Answer:

The distance is shortenend by factor .1715

Explanation:

5 n  = 1/r^2

sqrt (1/5) = r

170 n  = 1 / ( x sqrt(1/5))^2

(xsqrt 1/5)^2 = 1/170

x sqrt 1/5  = .076696

x = .1715    

5 0
2 years ago
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