Answer:
No
Reasoning:
If something is a perfect cube, it is able to be put under a cube root (![\sqrt[3]{..}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B..%7D)
) and will result in an integer (a non-decimal number > 0, basically).
So let's calculate ![\sqrt[3]{48}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D)
, and see if the result is an integer.
= 3.634.......
As you can see, the result is not an integer, therefore 48 is not a perfect cube.
Answer: A. 55°
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
Answer:
A) No
B) No
C) Yes
Step-by-step explanation:
A) 2 out of three observations is equal to
2/3 = 0.67 or 67 %
We know tha the interval
[μ - σ/2 , μ + σ/2] is approximately 68.3 % of the values
Therefore 2 out of 3 would not fall in that interval
B)
4 out of 5 is 4/5 = 0,8 or 80 % If we examine the interval
[μ - σ , μ + σ ] which is approximately 95. Then value 4/5 ( 0,8)
Therefore 0,8 is out of the interval
C) 19/20 = 0,95 or 95 % is almost exact the value for the interval
[μ - 1.5σ , μ + 1.5σ ] That value is inside μ - 2σ , μ + 2
You know what its probably 7.44
