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Answer:
(a) Anova table is attached below.
(b) The population means of milk yield are different among the three diet types
Step-by-step explanation:
In this case we need to perform a One-way ANOVA to determine whether the effect of three diet types on the milk yield of cows are significantly different or not.
The hypothesis can be defined as follows:
<em>H</em>₀: The effect of three diet types on the milk yield of cows are same.
<em>Hₐ</em>: The effect of three diet types on the milk yield of cows are significantly different.
(a)
The formulas are as follows:
The F critical value is computed using the Excel formula:
F critical value=F.INV.RT(0.05,2,24)
The ANOVA table is attached below.
(b)
The rejection region is defined as follows:
F > F (2, 24) = 3.403
The computed F statistic value is:
F = 34.069
F = 34.269 > F (2, 24) = 3.403
The null hypothesis will be rejected.
Thus, concluding that the population means of milk yield are different among the three diet types
Consider the polynomial .
For this polynomial to be trinomial with a degree of 3. We have to identify the missing exponent of the 'y' term.
Let the missing exponent of the 'y' term be 0
So, the polynomial will be
=
= which is not a trinomial, which is a binomial.
So, the missing exponent of 'y' can'not be zero.
Let the missing exponent of the 'y' term be 2
So, the polynomial will be
=
= which is a trinomial of degree 4.
So, the missing exponent of 'y' can'not be '2'.
If we will take the missing exponent of 'y' more than 2, than the degree of the given polynomial will not be 3 anymore.
Let the missing exponent of the 'y' term be 1
So, the polynomial will be
=
= which is a trinomial of degree 3
So, the missing exponent of 'y' is 1.