Answer:
sin(θ)^2 + tan2θ + sin(θ)^2 + cosθsinθ - cos(θ)^2. sinθ.tan2θ - cos(θ)^2 . sinθ - cos(θ)^2 / cosθsinθ
-- the greatest common factor of the 15, the 9, and the 24 is 3 .
-- the greatest common factor of the b⁴, the b⁵, and the b³ is b³.
-- the greatest common factor of the c³, the c², and the c¹, is c¹.
-- the greatest common factor of the d², the d¹, and the d³ is d¹.
-- SO, the greatest common factor of the whole thing is ( 3 b³ c d ) .
Can you factor that out of the big mess ?
Please try it.
You should get (3 b³cd) (5 bc²d - 3 b²c - 8 d²) .
Answer:
- 7 faces
- 15 edges
- 10 vertices
Step-by-step explanation:
This is a counting problem. As with many counting problems, it is helpful to adopt a strategy that helps ensure you count everything only once.
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<h3>Faces</h3>
There are two pentagonal faces and 5 rectangular faces for a total of ...
7 faces
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<h3>Edges</h3>
There are 5 edges around each of the pentagonal faces, and 5 edges connecting the top face to the bottom faces, for a total of ...
15 edges
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<h3>Vertices</h3>
There are 5 vertices on the top face, and 5 on the bottom face, for a total of ...
10 vertices