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Aliun [14]
2 years ago
6

How to find where inflection points are.

Mathematics
2 answers:
Rashid [163]2 years ago
8 0
An inflection point is a point on the graph of a function at which the concavity changes. Points of inflection can occur where the second derivative is zero. In other words, solve f '' = 0 to find the potential inflection points. Even if f ''(c) = 0, you can't conclude that there is an inflection at x = c.
Dmitrij [34]2 years ago
6 0
Here’s the answer !! have a good day
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Which is the equation for the line that has a slope of 12 and passes through the point (3, 20)?
Anna007 [38]

Answer:

the first one

Step-by-step explanation:

y-y1=m(x-x1)

y-20=12(x-3)

y-20+20=12\left(x-3\right)+20

simplify:

y=12x-16

4 0
3 years ago
Delilah does 184184184 jumping jacks in 444 minutes. She does her jumping jacks at a constant rate. How many jumping jacks can D
valkas [14]
I'm assuming you didn't mean to repeat each number 3 times. 

If she did 184 jumping jacks in 4 minutes that means she did 46 jumping jacks per minute. 
4 0
3 years ago
Read 2 more answers
If Sabrina has seven letters, with no repeats, how many possible arrangements are there with the seven letters.
MissTica

Answer:

5040

Step-by-step explanation:

There are 7 possibilities for the first spot, 6 for the second, etc.

7*6*5*4*3*2*1=5040

3 0
2 years ago
How to do this ?<br> Don’t understand it
riadik2000 [5.3K]
X=y+3
<span>-5x-4y=<span>30
-------------------
Substitute y + 3 for x in </span></span>-5x-4y=30
<span><span>-5<span>(y+3)-</span></span>4y</span>=<span>30
</span>-9y-15=<span>30
</span>----------------------------
Add 15 to each side
<span><span>-9y-15</span>+15</span>=<span>30+<span>15
-9y = 45
</span></span>-----------------------------------
Divide each side by -9
-9y ÷ -9 = 45 ÷ -9
y = -5
Now we solve for x
====================================================================
Substitute -5 for y in x = y + 3
x=-<span><span>5</span>+<span>3
</span></span>x = -2
----------------------
(-2,-5) is your answer


7 0
3 years ago
suppose that you have 3000$ to invest. which investment yields the greater return over a 10 year period: 8.04% compounded daily
Ksenya-84 [330]

Answer:  Option A: 8.04% compounded daily

<u>Step-by-step explanation:</u>

A = P\bigg(1+\dfrac{r}{n}\bigg)^{nt}\qquad where\\\\\bullet A = \text{accrued amount (principal plus interest earned)}\\\bullet P = \text{principal (amount invested)}\\\bullet r = \text{rate (in decimal form)}\\\bullet n=\text{number of times compounded in one year}\\\bullet t=\text{time (number of years)}\\\\\\Option\ A:\\A = \text{unknown}\\P=3000\\r=8.04\%\rightarrow 0.0804\\n=\text{daily}\rightarrow 365\\t=10\\\\A=3000\bigg(1+\dfrac{0.0804}{365}\bigg)^{365\times 10}\\\\.\ =\$ 6,702.79

Option\ B:\\A = \text{unknown}\\P=3000\\r=8.1\%\rightarrow 0.081\\n=\text{quarterly}\rightarrow 4\\t=10\\\\A=3000\bigg(1+\dfrac{0.081}{4}\bigg)^{4\times 10}\\\\.\ =\$ 6,689.37

Option A results in the greater amount of money.

7 0
3 years ago
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