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Tamiku [17]
3 years ago
11

What property of water enables ice wedging to break rock?

Chemistry
1 answer:
seropon [69]3 years ago
6 0

Answer:

c

Explanation:

hope I helped

hope im corrext

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Give 10 chemical properties of common polymers​
algol [13]

Answer:

Some of the useful properties of various engineering polymers are high strength or modulus to weight ratios (light weight but comparatively stiff and strong), toughness, resilience, resistance to corrosion, lack of conductivity (heat and electrical), color, transparency, processing, and low cost

Explanation:

3 0
3 years ago
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You have 150 g of water (m). The specific heat of the water is 4.184 g/jC (c) . You heat the water and raise the temperature by
marta [7]

Answer:

627.6J

Explanation:

q=mcΔT

where:

q = heat energy (J)

m = mass (g)

c = specific heat (g/j*C)

Δt = change in temperature (C/K)

q= (150)(4.184)(1) = 627.6

8 0
3 years ago
Disposal site for solid waste
Alexxandr [17]

Answer:

"where deliberately discarded solid waste is discharged, deposited, injected, dumped, spilled, leaked, or placed so that such solid waste or a constituent thereof may enter the environment or be emitted into the air or discharged into waters, including ground waters."

Explanation:

https://definitions.uslegal.com/s/solid-waste-disposal-site/

7 0
3 years ago
A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume
alexandr402 [8]

Answer:

x_{N_2F_2}= 0.415\\\\x_{SF_6}=0.585

Explanation:

Hello!

In this case, since the mole fraction of both gases in the tank is computed via:

x_{N_2F_2}=\frac{n_{N_2F_2}}{n_{N_2F_2}+n_{SF_6}} \\\\x_{SF_6}=\frac{n_{SF_6}}{n_{N_2F_2}+n_{SF_6}}

It means we need to compute the moles of each gas, just as it is shown down below:

n_{N_2F_2}}=5.53gN_2F_2*\frac{1molN_2F_2}{66.01gN_2F_2} =0.0838molN_2F_2\\\\n_{SF_6}=17.3gSF_6*\frac{1molSF_6}{146.06gSF_6} =0.118molSF_6

Thus, the mole fractions turn out:

x_{N_2F_2}=\frac{0.0838mol}{0.0838mol+0.118mol}= 0.415\\\\x_{SF_6}=\frac{0.0838mol}{0.0838mol+0.0838mol}=0.585

Best regards!

8 0
3 years ago
¿Cuál es la Molaridad y Normalidad de 230 grs de HCl disueltos en 680 ml de agua?<br> Cl: 35,5 grs
adelina 88 [10]

Answer:

English? please

Explanation:

4 0
3 years ago
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