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Y_Kistochka [10]
2 years ago
10

How do the linear equation and quadratic equation are differ? What do we suffer on earth? What if we would live on the moon /sun

?​
Physics
2 answers:
irakobra [83]2 years ago
6 0
Quadratic equation is any equation that can be rearranged in standard form as ax^{2}+box+c=0
Aleksandr [31]2 years ago
4 0

A quadratic equation is a parabola and a linear equation is a straight line.

  • Quadratic Equation is an equation in which the power of variable mostly x is two.
  • Standard quadratic equation is  ax^{2} +bx+c=0
  • Any linear equation have form like y=mx+c
  • The moon has no atmosphere, no weather and no oceans of water. Its surface is in a perpetual vacuum.
  • Because the moon's gravity is only one-sixth that of the Earth's gravity, Apollo astronauts had to risk of stumbling or falling.
  • Astronauts on the moon were protected from the extreme temperatures by their spacesuits. The suits had several layers of insulating material covered by a highly reflective outer layer.

Learn more:

brainly.com/question/9201543

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You get 3 times heavier
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Describing motion with velocity-time graphs.
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5 0
3 years ago
Which of the following may have happened if the inner planets had greater masses during the formation of the solar system? . . A
Svetach [21]
Right answer is option b that is the inner planet may havebeen larger and more gaseous.
5 0
3 years ago
A 25 kg circular disk has a diameter of 2.5 feet and a thickness of 2.5 cm. Find the density of the disk in kg/m3. Next, find th
Gre4nikov [31]

Answer:

Assume that \rm g= 9.81\; N\cdot kg^{-1}; \rho(\text{Water}) = \rm 1000\;kg\cdot m^{-3}.

Density of the disk: approximately \rm 2.19\times 10^{3}\; kg\cdot m^{-3}.

Weight of the disk: approximately \rm 245\;N.

Buoyant force on the disk if it is submerged under water: approximately \rm 112\; N.

The disk will sink when placed in water.

Explanation:

Convert the dimensions of this disk to SI units:

  • Diameter: d = \rm 25\; inches = (25\times 0.3048)\; m = 0.762\;m.
  • Thickness h = \rm 2.5\; cm = (2.5\times 0.01)\; m = 0.025\;m.

The radius of a circle is 1/2 its diameter:

\displaystyle r = \rm \frac{1}{2}\times 0.762\;m = 0.381\; m.

Volume of this disk:

V(\text{disk}) = \pi\cdot r^{2}\cdot h = \pi\times 0.381^{2}\times 0.025 \approx 0.0114009\; m^{3}.

Density of this disk:

\displaystyle \rho(\text{disk}) = \frac{m}{V} = \rm \frac{25\; kg}{0.0114009\; m^{3}} = 2.19\times 10^{3}\;kg\cdot m^{-3}.

\rho(\text{disk}) >\rho(\text{water}) indicates that the disk will sink when placed in water.

Weight of the object:

W(\text{disk}) = m\cdot g = \rm 25\times 9.81 = 245.25\; N.

The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately \rm 0.0114009\; m^{3} of water. The buoyant force on the disk will be:

\begin{aligned}F(\text{buoyant force}) &= W(\text{Water Displaced}) \\& = \rho\cdot V(\text{Water Displaced})\cdot g\\ & = \rm 1\times 10^{3}\; kg\cdot m^{-3}\times 0.0114009\; m^{3}\times 9.81\; N\cdot kg^{-1}\\ &\approx \rm 112\; N\end{aligned}.

The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.

3 0
3 years ago
Nathan has a car that accelerates at 5 m/s2. If the car has a mass of
zhannawk [14.2K]

Answer:

F = 5000 [N] or 5 [kN]

Explanation:

In order to solve this problem we must take into account Newton's second law, which tells us that the sum of all forces applied on a body must be equal to the product of the mass of the body by its acceleration.

F = m*a

where:

F = force [N]

m = mass = 1000 [kg]

a = acceleration = 5 [m/s^2]

F = (1000*5)

F = 5000 [N] or 5 [kN]

5 0
3 years ago
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