This link should help you out!!
http://mszopiak.weebly.com/uploads/5/5/8/1/55815541/p_vtgraphskey_mszopiak.pdf
Right answer is option b that is the inner planet may havebeen larger and more gaseous.
Answer:
Assume that
;
.
Density of the disk: approximately
.
Weight of the disk: approximately
.
Buoyant force on the disk if it is submerged under water: approximately
.
The disk will sink when placed in water.
Explanation:
Convert the dimensions of this disk to SI units:
- Diameter:
. - Thickness
.
The radius of a circle is 1/2 its diameter:
.
Volume of this disk:
.
Density of this disk:
.
indicates that the disk will sink when placed in water.
Weight of the object:
.
The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately
of water. The buoyant force on the disk will be:
.
The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.
Answer:
F = 5000 [N] or 5 [kN]
Explanation:
In order to solve this problem we must take into account Newton's second law, which tells us that the sum of all forces applied on a body must be equal to the product of the mass of the body by its acceleration.
F = m*a
where:
F = force [N]
m = mass = 1000 [kg]
a = acceleration = 5 [m/s^2]
F = (1000*5)
F = 5000 [N] or 5 [kN]