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Nadusha1986 [10]
4 years ago
14

What is the law of conservation of matter

Physics
2 answers:
Ainat [17]4 years ago
7 0

Answer:

Matter cannot be created or destroyed.

Explanation:

APEX

Goryan [66]4 years ago
6 0

Answer:

The law of conservation of matter (or mass), also known as the Law of Lomonosov-Lavoisier, states the following:

<em>"In a chemical reaction the sum of the mass of the reactants is equal to the sum of the mass of the products." </em>

Hence the famous phrase:

<em>"The mass is not created or destroyed, it only transforms." </em>

This was raised by the Russian scientist Mikhail Lomonosov in 1748 and independently discovered years later by the French chemist Antoine Lavoisier in 1785.

It should be noted that this principle is quite accurate for low-energy chemical reactions, but for nuclear reactions (collisions between particles at high energies), this classical definition does not apply (the total mass of the system does not have to be strictly conserved) and must be taken into account the equivalence between mass and energy that was postulated in Albert Einstein's theory of relativity:

<em> "The amount of mass-energy that manifests a certain space-time is constant throughout the universe." </em>

Being this expressed mathematically by his famous equation where he relates the energy E with the mass m and the speed of light c:

E=mc^{2}

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A train at a constant 79.0 km/h moves east for 27.0 min, then in a direction 50.0° east of due north for 29.0 min, and then west
ivolga24 [154]

Answer:

Magnitude of avg velocity, |v_{avg}| = 18.9 km/h

\theta' = 56.85^{\circ}

Given:

Constant speed of train, v = 79 km/h

Time taken in East direction, t = 27 min = \frac{27}{60} h

Angle, \theta = 50^{\circ}

Time taken in 50^{\circ}east of due North direction, t' = 29 min =  \frac{29}{60} h

Time taken in west direction, t'' = 37 min =  \frac{27}{60} h

Solution:

Now, the displacement, 's' in east direction is given by:

\vec{s} = vt = 79\times \frac{27}{60} = 35.5\hat{i} km

Displacement in  50^{\circ} east of due North for 29.0 min is given by:

\vec{s'} = vt'sin50^{\circ}\hat{i} + vt'cos50^{\circ}\hat{j}

\vec{s'} = 79(\frac{29}{60})sin50^{\circ}\hat{i} + 79(\frac{29}{60})cos50^{\circ}\hat{j}

\vec{s'} = 29.25\hat{i} + 24.54\hat{j} km

Now, displacement in the west direction for 37 min:

\vec{s''} = - vt''hat{i} = - 79\frac{37}{60} = - 48.72\hat{i} km

Now, the overall displacement,

\vec{s_{net}} = \vec{s} + \vec{s'} + \vec{s''}

\vec{s_{net}} = 35.5\hat{i} + 29.25\hat{i} + 24.54\hat{j} - 48.72\hat{i}

\vec{s_{net}} =  16.03\hat{i} + 24.54\hat{j} km

(a) Now, average velocity, v_{avg} is given:

v_{avg} = \frac{total displacement, \vec{s_{net}}}{total time, t}

v_{avg} = \frac{16.03\hat{i} + 24.54\hat{j}}{\frac{27 + 29 + 37}{60}}

v_{avg} = 10.34\hat{i} + 15.83\hat{j}) km/h

Magnitude of avg velocity is given by:

|v_{avg}| = \sqrt{(10.34)^{2} + (15.83)^{2}} = 18.9 km/h

(b) angle can be calculated as:

tan\theta' = \frac{15.83}{10.34}

\theta' = tan^{- 1}\frac{15.83}{10.34} = 56.85^{\circ}

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The human ear is most sensitive to the sounds in what range?
jeyben [28]

Answer:

The human ear is most sensitive to sounds in the range of 2000 to 3000 Hz

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Andy has been consuming a set number of calories and recently added an additional 100 calories in the form of a daily snack. Alt
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Increase his activity and exercise levels and add more calories to gradually gain weight

Explanation:

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Which form of energy does the motor convert most of its electric energy into?
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Why are heat transfers associated with phase changes known as latent or "hidden" heats?
pshichka [43]
The best and most correct answer among the choices provided by your question is the first choice or letter A.

Heat transfers associated with phase changes known as latent or "hidden" heats because h<span>eat absorbed or released in a phase change is measured in kJ while temperature is measured in °C.</span>


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
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