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Agata [3.3K]
2 years ago
6

What is the number of moles of potassium chloride present in 142 g of kcl?

Chemistry
1 answer:
morpeh [17]2 years ago
5 0

Answer:

98.3!

Explanation:

Hope this helps! :)

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True or false a solid has a constant shape and volume
dusya [7]
The answer you are looking for is True
8 0
3 years ago
A beaker containing 6.32 moles of PBr3, contains___
NISA [10]

Answer:

3.8 x 10²⁴molecules

Explanation:

Given parameters:

Number of moles  = 6.32moles

Unknown:

Number of molecules  = ?

Solution:

The number of moles can be used to derive the number of molecules found within a substance.

Now,

       1 mole of substance contains 6.02 x 10²³ molecules

     6.32 mole of PBr₃ will contain 6.32 x 6.02 x 10²³ = 3.8 x 10²⁴molecules

8 0
3 years ago
Most of our DNA consists of regions that do not code for any proteins True or False
Lady bird [3.3K]
The Answer you are looking for is true
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3 years ago
400. mg of an unknown protein are dissolved in enough solvent to make 5.00 mL of solution. The osmotic pressure of this solution
ch4aika [34]

<u>Answer:</u> The molecular weight of protein is 1.14\times 10^2g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

or,

\pi=i\times \frac{m_{solute}\times 1000}{M_{solute}\times V_{solution}\text{ (in mL)}}}\times RT

where,

\pi = Osmotic pressure of the solution = 0.0861 atm

i = Van't hoff factor = 1 (for non-electrolytes)

m_{solute} = mass of protein = 400 mg = 0.4 g   (Conversion factor:  1 g = 1000 mg)

M_{solute} = molar mass of protein = ?

V_{solution} = Volume of solution = 5.00 mL

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[25+273]K=298K

Putting values in above equation, we get:

0.0861atm=1\times \frac{0.4g\times 1000}{M\times 100}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\M=1136.62g/mol=1.14\times 10^2g/mol

Hence, the molecular weight of protein is 1.14\times 10^2g/mol

4 0
3 years ago
How many O2 molecules can be made with the oxygen from 492 g of sodium phosphate?
serg [7]
<span>To answer this question, you need to change the sodium phosphate unit into mol and doing the reaction. Sodium phosphate or Na3PO4  molecular weight is 163.94 or 164 rounded up. Then the amount should be: 492g/ (164g/mol)= 3 mol

For every 1 mol of </span>Na3PO4  there are 4 mol of oxygen element. To made 1 mol of O2 molecule, you will need 2 mol oxygen element. Then the amount of oxygen should be: 4/2 * 3 mol= 6 mol * 6.02 * 10^23= 36.12 * 10*23= 3.61 * 10^24

7 0
3 years ago
Read 2 more answers
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