Triangle ABC and triangle DCE are congruent, so line DE = line AB
Use the cosine rule to find angle ACB
Angle ACB = 48.1°
Answer:
<h3>
Acute Angles: ∠TLS, ∠SLT, ∠ULR</h3><h3>
Right Angles: ---------</h3><h3>
Obtuse Angles: ∠RLT, ∠SLU, ∠ULS,</h3><h3>
Straight Angles: ∠RLS, ∠TLU </h3><h3>
Not angles: ∠TRL </h3>
Step-by-step explanation:
The lines intersect at point L, so all angles have a vertex (middle letter) L so there is no angle TRL
Straight angle is a line with dot-vertex, so the straight angles are ∠RLS and ∠TLU.
∠TLS is less than 90° then it is acute angle (∠SLT is the same angle). ∠ULR is vertex angle to ∠TLS, so it's also acute angle.
Two angles adding to straight angle mean that they are both right angles or one is acute and the second is obtuse. ∠TLS is acute so ∠RLT is obtuse (they adding to ∠RLS) and ∠SLU is obtuse (they adding to ∠TLU). ∠ULS is the same angle as ∠SLU.
Answer:
-140 ft is not a distance
Step-by-step explanation:
Distance must be a positive number
-140 is negative
Answer:
Step-by-step explanation:
<h2>A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
</h2><h2>y=-16x^2+129x+119
</h2><h2>y=−16x </h2><h2>2
</h2>
+129x+119
Neither is correct. please try again and re-ask for answers or hint.
