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3 years ago

Mr.Keaton planted 918 cornstalks there are 9 cornstalks in each row how many rows of corn did he plant

Mathematics

2 answers:

kondor19780726 [428]3 years ago

6 0

Answer:

I think 102 rows of corn

Step-by-step explanation:

918 ÷ 9 = 102

Alexeev081 [22]3 years ago

5 0

918 / 9 = 102 rows.

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25 POINTS PLS HELP IM WAISTING ALL MY POINTS

faust18 [17]

Answer:

2680 is the answer

Step-by-step explanation:

1. 3.2+3.5=6.7

2. 6.7*400

3. 2680

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3 years ago

I need help with the area and perimeter

Lady_Fox [76]

Answer:

Area would be 122.

Perimeter would be 45.

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3 years ago

Set up an equation to find the length of the diagonal of the rectangle.

nikklg [1K]

Answer:

Set length as l

Use the Pythagorean Theorem to find the diagonal:

$5^{2} +l^{2} =(\sqrt{125})^{2}\\ 5^{2} +l^{2} =125$

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3 years ago

Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of

Naddik [55]

Answer:

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

Step-by-step explanation:

For each U.S. resident, there are only two outcomes possible. Either they have blood type AB, or they do not. This means that we can solve this problem using binomial probability distribution concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

50 U.S residents are sampled, so $n = 50$

4% of the U.S population has blood type AB, so $p = 0.04$ .

What is the probability that exactly 2 of the U.S. residents have blood type AB?

This is P(X = 2). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{50,2}.(0.04)^{2}.(0.96)^{48} = 0.2762$

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

5 0

3 years ago

A state is considering license plates that have two digits followed by four letters. Assuming no combinations are excluded, how

love history [14]

Answer:

32,292,000

Step-by-step explanation:

In your question, it asks how many license plate combinations we could make WITHOUT repeats.

We need some prior knowledge to answer this question.

We know that:

There are 26 letters in the alphabet
We can make 10 digits (0 - 9)

With the information we know above, we can solve the question.

Since we CAN'T have repeats, we would be excluding a letter or number for each license plate.

We're going to need to multiply each "section" in order to find how many combinations of license plates we can make.

We decrease by one letter and one number in each section since we can't have repeats.

Now, we can solve.

Work:

$26*25*24*23*10*9 = 32,292,000$

When you're done multiplying, you should get 32,292,000.

This means that there could be 32,292,000 different combinations of license plates.

<h3>I hope this helps you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>

8 0

4 years ago

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