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2 years ago

Please help me because I don't know how to calculate mol and gram

Chemistry

1 answer:

ehidna [41]2 years ago

7 0

Answer:

1 mol= 98 g

Explanation:

The formula for sulfuric acid is H2SO4. The molar mass of sulfuric acid is 98.07848 g mol.

What is the gram molecular weight of H2SO4’.Just add together the individual atomic weights,(2X1)+32+(4x16)=98gms

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The decomposition of dinitrogen tetraoxide into nitrogen gas and oxygen gas is shown by which balanced chemical equation?

LekaFEV [45]

Know what decomposition is. The compound is "breaking down".

Di means 2 while, Tetra means 4.

First, we will simply follow the instructions and break down the compound as so: The decomposition of dinitrogen tetraoxide into nitrogen gas and oxygen gas

*Take into account that diatomic molecules (HNOFClBRI) will always have a subscript of 2

N₂O₄⇒N₂+O₂

After breaking down the compound, we must now balance the equation.

To balance the equation, we must make sure that each element has the same amount of atoms.

Starting with compound at the left of the yield: N=2 and O=4
But, at the right of the yield: N=2 and O=2
We have now discovered that the oxygen gas is not balanced throughout the equation.

N₂O₄⇒N₂+2O₂

*We simply multiply the oxygen gas on the right of the equation by 2

After multiplying, on the right side of the equation, O=4. We now have a balanced equation because all elements have the same amount of atoms on each side.

So your final answer for this balanced decomposition chemical equation is: N₂O₄⇒N₂+O₂

6 0

4 years ago

Find the average speed of a person who swims 105 m in 70 s

spin [16.1K]

Answer:

v = 1.5 m/s

Explanation:

Given that,

Distance covered by a person, d = 105 m

Time taken, t = 70 s

We need to find the average speed of the person. We know that the average speed is given by :

$v=\dfrac{d}{t}\\\\v=\dfrac{105\ m}{70\ s}\\\\v=1.5\ m/s$

So, the average speed of the person is equal to 1.5 m/s.

4 0

3 years ago

Formation of hydrogen bonds requires hydrogen atoms and what else? polar covalent bonds water ionic bonds oxygen

jeyben [28]

Formation of hydrogen bonds require hydrogen atoms and Oxygen atoms, fluorine atoms, or nitrogen atoms.

Hydrogen bond is a special case of dipole-dipole force of attractions. Here there are two polar molecules in which one of them has hydrogen atom with partial positive charge on it and the other molecule can be O, F or N with partial negative charge. Since, these dipole-dipole force of attractions are stronger than other dipole-dipole force of attractions we name it as Hydrogen bonds.

Some of the examples where hydrogen bonding is present are- H₂O, HF, NH₃ etc

Since, Hydrogen bonds are a type of dipole-dipole forces of attraction, they are present in polar covalent molecules.

To know more about Hydrogen bonds here

brainly.com/question/10904296

#SPJ4

3 0

1 year ago

Generally, does the size of a radioactive sample affect half-life?

Natasha2012 [34]

Answer:

The quantity of radioactive nuclei at any given time will decrease to half as much in one half-life.

Explanation:

4 0

3 years ago

Read 2 more answers

For many weak acid or weak base calculations, you can use a simplifying assumption to avoid solving quadratic equations. Classif

shtirl [24]

Answer:

a. not valid

b. valid

c. not valid

d. valid

e. not valid

Explanation:

The assumption to avoid solving the quadratic equation for the calculation of [H⁺] and [OH⁻] involved in the equilibria of weak acids and bases ( small Ka and Kb) is valid as long as the value obtained from the shortcut is less than 5 % or less of the original acid or base concentration.

For a general monoprotic acid, as in this question, the equlibria is:

HA + H₂O ⇄ H₃O⁺ + A⁻ Ka = [H₃O⁺][A⁻]/[HA]

To determine the concentrations at equilibrium we are going to setupup the ICE table:

[HA] [H₃O] [A⁻]

Initial [HA]₀ 0 0

Change - x +x +x

Equil [HA]₀ - x x x

Ka = x² / [HA]₀ - x

Here is where we make our simplification of approximating [HA]₀ - x to the original acid concentration, [HA]₀, assuming x is much less than [HA] since HA is a weak acid.

To answer our questions we will solve for x,and then can compare it to the initial HA concentration.

Lets now perform our calculations.

(a) x = √ (0.01 x 1x 10⁻⁴) = 1 x 10⁻³ M = [H₃O⁺]

% = 1 x 10⁻³/.01 x 100 = 10%

The assumption is not valid.

(b) x = √ (0.01 x 1x 10⁻⁵) = 3.2 x 10⁻⁴ M = [H₃O⁺]

% = 3.2 x 10⁻⁴ /0.01 x 100 = 3.2 %

The assumption is valid since the criteria of 5 % or less has been met.

% = 1.0 x 10⁻² /0.1 x 100 = 10 %

The assumption is not valid, we wiould have to solve the quadratic equation.

(d) x = √ (1 x 1x 10⁻³) = 3.2 x 10⁻² M = [H₃O⁺]

% = 3.2 x 10⁻² / 1 x 100 = 3.2

The assumption is valid.

(e) x = √ (0.001 x 1x 10⁻⁵) =1.0 x 10⁻⁴ M = [H₃O⁺]

% = 1.0 x 10⁻⁴ / .001 = 10 %

The assumption is not valid and one has to solve the quadratic equation.

7 0

3 years ago