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Monica [59]
3 years ago
11

The first-order decomposition of n2o at 1000 k has a rate constant of 0.76 s-1. if the initial concentration of n2o is 10.9 m, w

hat is the concentration of n2o after 9.6 s
Chemistry
1 answer:
Reptile [31]3 years ago
3 0
For a first-order reaction, the rate law would be expressed as:<span>

r = dC / dt = -kC

Integrating it from time zero and the initial concentration, Co, to time, t, and the final concentration, C. We will obtain the first-order integrated law as follows:

ln C/Co= -kt

To determine the concentration of N2O in the system at a certain time, we simply substitute the given values from the problem statement as follows:

</span>ln C / Co = -kt<span>
ln C / 10.9 = -0.76 (9.6)
e^ln C / 10.9 = e^-0.76 (9.6)
C / 10.9 = 6.78 x 10^-4
C= 7.39 x 10^-3 m
<span>
Therefore, the concentration of N2O in the system after 9.6 s would be 7.39 x10^-3 m.
</span></span><span><span>
</span></span>
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Problem 4
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<h3>Answer:</h3>

1.93 g

<h3>Explanation:</h3>

<u>We are given;</u>

The chemical equation;

2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l) ΔH = -3120 kJ​

We are required to calculate the mass of ethane that would produce 100 kJ of heat.

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Number of moles that will produce 100 kJ will be;

= (2 × 100 kJ) ÷ 3120 kJ)

= 0.0641 moles

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Mass of ethane = 0.0641 moles × 30.07 g/mol

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Thus, the mass of ethane that would produce 100 kJ of heat is 1.93 g

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2.5128e10 is the answer
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<h3>What are catalysts?</h3>

Catalysts are substances that are utilized in reactions that are not themselves consumed in reactions but only speed up the rate of the reactions.

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