Answer:
37.58 g of FeCl₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Fe + 2HCl —> FeCl₂ + H₂
Next, we shall determine the mass of HCl that reacted and the mass of FeCl₂ produced from the balanced equation. This is can be obtained as follow:
Molar mass of HCl = 1 + 35.5 = 36.5 g/mol
Mass of HCl from the balanced equation = 2 × 36.5 = 73 g
Molar mass of FeCl₂ = 56 + (2×35.5)
= 56 + 71
= 127 g/mol
Mass of FeCl₂ from the balanced equation = 1 × 127 = 127 g
SUMMARY:
From the balanced equation above,
73 g of HCl reacted to produced 127 g of FeCl₂.
Finally, we shall determine the mass of FeCl₂ produced by the reaction of 21.6 g of HCl. This can be obtained as follow:
From the balanced equation above,
73 g of HCl reacted to produced 127 g of FeCl₂.
Therefore, 21.6 g of HCl will react to produce = (21.6 × 127)/73 = 37.58 g of FeCl₂.
Thus, 37.58 g of FeCl₂ were obtained from the reaction.
