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True [87]
2 years ago
14

How many grams of CO2 should be placed in a 250 mL container and -24°C to produce a pressure of 95K PA?

Chemistry
1 answer:
klasskru [66]2 years ago
7 0

Answer:

About 0.53 g of carbon dioxide needs to be added.

Explanation:

Recall the ideal gas law:

\displaystyle PV = n RT

To determine the amount of carbon dioxide we need, we need to solve for <em>n: </em>

<em />\displaystyle n = \frac{PV}{RT}<em />

<em />

Recall that <em>P</em>, <em>V</em>, and <em>T</em> are in atm, L, and K, respectively. <em>R</em> is the universal gas constant.

Convert all values into the correct units:

Volume:

\displaystyle 250\text{ mL } \cdot \frac{1 \text{ L}}{1000 \text{ mL}} = 0.25 \text{ L}

Temperature:

\displaystyle \begin{aligned} K & =( ^\circ C) + 273.15 \\ \\ & = (-24) + (273.15) \\ \\ & = 249 \text{ K}\end{aligned}

And pressure:

\displaystyle 95 \text{ kPa} \cdot \frac{1.00 \text{ atm}}{101.3 \text{ kPa}} = 0.94 \text{ atm}

Substitute and evaluate:

\displaystyle\begin{aligned}  n & = \frac{\left(0.94 \text{ atm}\right)\left(0.25 \text{ L}\right)}{\left(\dfrac{0.08206 \text{ L-atm}}{\text{mol-K}}\right)\left(249\text{ K}\right)} \\ \\ & = 0.012 \text{ mol CO$_2$}\end{aligned}

Convert moles to grams:

\displaystyle 0.012 \text{ mol CO$_2$} \cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} = 0.53 \text{ g CO$_2$}

In conclusion, about 0.53 g of carbon dioxide needs to be added.

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3 years ago
An ordered list of chemical substances is shown.
alina1380 [7]

Answer : The correct option is, (C) 2, 4 and 5.

Explanation :

Combustion reaction : It is a type of reaction in which a hydrocarbon react with an oxygen molecule to give carbon dioxide, water as a product.

For example : Methane react with oxygen to give carbon dioxide and water.

CH_4+2O_2\rightarrow CO_2+2H_2O

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In the given list, C_2H_5NH_2 is the only hydrocarbon which shows a combustion reaction. That means C_2H_5NH_2 react with O_2 to give CO_2,H_2O and N_2 as a product.

The balanced combustion reaction of C_2H_5NH_2 is,

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8 0
3 years ago
This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): An analytical chemist has det
jeyben [28]

Answer:

0.054 mol O

Explanation:

<em>This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of carbon in a sample of acetic acid. How many moles of oxygen are in the sample?</em>

<em />

Step 1: Given data

  • Chemical formula of acetic acid: CH₃CO₂H
  • Moles of carbon in the sample: 0.054 moles

Step 2: Establish the appropriate molar ratio

According to the chemical formula, the molar ratio of C to O is 2:2.

Step 3: Calculate the moles of oxygen in the sample

We will use the molar ratio to determine the moles of oxygen accompanying 0.054 moles of carbon.

0.054 mol C × (2 mol O/2 mol C) = 0.054 mol O

6 0
3 years ago
what is the most appropriate unit to measure the following; the length of a football field. b) the diameter of a tennis ball​
hjlf

Explanation:

a) m (metre)

b) mm (millimeter)

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