<h3>
Answer:</h3>
5.55 mol C₂H₅OH
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Tables
- Moles
<u>Stoichiometry</u>
- Using Dimensional Analysis
- Analyzing Reactions RxN
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
[Given] 500. g C₆H₁₂O₆ (Glucose)
[Solve] moles C₂H₅OH (Ethanol)
<u>Step 2: Identify Conversions</u>
[RxN] 1 mol C₆H₁₂O₆ → 2 mol C₂H₅OH
[PT] Molar mass of C - 12.01 g/mol
[PT] Molar Mass of H - 1.01 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol
<u>Step 3: Stoichiometry</u>
- [DA] Set up conversion:

- [DA} Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
5.55001 mol C₂H₅OH ≈ 5.55 mol C₂H₅OH
The correct answer to your question is
Basic. it is the is the basic unit of non living things.
Hope this helps!
There are three methods of thermal energy transfer: conduction, convection, and radiation. Air molecules that come into contact with the warmer land and surface of the oceans and lakes increase their thermal energy through conduction.
If the wavelength of the wave is increased to 10 m, the frequency of the wave will be 60 Hz
<h3>Data obtained from the question </h3>
- Wavelength (λ) = 10 m
- Velocity (v) = 600 m/s
<h3>How to determine the frequency of the wave </h3>
The frequency, wavelength and velocity of a wave are related according to the following equation:
Frequency (f) = velocity (v) / wavelength (λ)
f = v / λ
With the above formula, we can obtain the frequency of the wave as follow
f = v / λ
f = 600 / 10
f = 60 Hz
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