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vichka [17]
3 years ago
10

The area of a rectangle is 36 square centimeters, and its length is 9 centimeters.

Mathematics
1 answer:
AveGali [126]3 years ago
7 0

Answer:

4

Step-by-step explanation:

36 divide by 9 = 4

4 goes into 36 9 times

For example

4,8,12,16,20,24,28,32,36

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Find the length of the diagonal AD in the pentagon ABCDE shown in the coordinate plane.
Xelga [282]

Answer:

\sqrt{73} units.

Therefore, Option C is correct.

Step-by-step explanation:

We have given a pentagon ABCDE

We need to calculate its length

That means we have to find the distance of AD

So, coordinates of A(1,6) and D(4,-2)

Using distance formula:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Here,x_1=1,y_1=6,x_2=4,y_2=-2

On substituting the values we will get:

\sqrt{(4-1)^2+(-2-6)^2}

On simplification:

\sqrt{3^2+(-8)^2}

\sqrt{9+64}

\sqrt{73}.

Hence, the length of AD is  \sqrt{73} units.

Therefore, Option C is correct.

6 0
4 years ago
Can somebody help me with this problem .<br>3.)find the perimeter of the object below.
AysviL [449]

Answer:

189

Step-by-step explanation:

Multiple 15 by 13 and get 195

Multiply 3 by 2 and get 6

Subtract 195 by 6 and get 189

Hope it helps

7 0
3 years ago
Read 2 more answers
|-9| + |12| = ?
antoniya [11.8K]

Answer:

21

Step-by-step explanation:

-9=9

9+12=21

6 0
2 years ago
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GIVING AWAY FREE ROBL0X ACCOUNT WITH R0BUX
aniked [119]

Answer:

Imagine playing R0bl0x

Step-by-step explanation:

( dont take it srsly lol im jk)

3 0
3 years ago
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How do you find the value of c that satisfy the equation:
victus00 [196]

Answer:

The value of c = -0.5∈ (-1,0)

Step-by-step explanation:

<u>Step(i)</u>:-

Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]

<u> Mean Value theorem</u>

Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

f^{l} (c)  = \frac{f(b) -f(a)}{b-a}

<u>Step(ii):</u>-

Given  f(x) = 4x² +4x -3 …(i)

Differentiating equation (i) with respective to 'x'

          f¹(x) = 4(2x) +4(1) = 8x+4

<u>Step(iii)</u>:-

By using mean value theorem

f^{l} (c)  = \frac{f(0) -f(-1)}{0-(-1)}

8c+4 = \frac{-3-(4(-1)^2+4(-1)-3)}{0-(-1)}

8c+4 = -3-(-3)

8c+4 = 0

8c = -4

c = \frac{-4}{8} = \frac{-1}{2} = -0.5

c ∈ (-1,0)

<u>Conclusion</u>:-

The value of c = -0.5∈ (-1,0)

         

<u></u>

8 0
3 years ago
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