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jarptica [38.1K]
2 years ago
7

A rectangular poster is 3 times as long as it is wide. A rectangular banner is 5 times as long

Mathematics
1 answer:
Arada [10]2 years ago
3 0

Rectangular Poster:

Length = 9

Width = 3

Rectangular Banner:

Length = 10

Width = 2

Hope this is helpful!

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Leslie earned $12 Friday, $20 Saturday, and $56 Sunday selling bracelets. If she sold each bracelet for the same amount of money
Amanda [17]

Answer:

$4

Step-by-step explanation:

12÷4=3

20÷4=5

56÷4=14

7 0
2 years ago
Complete the steps in solving the quadratic function 7x – 9 = 7x2 – 49x by completing the square. –9 = 7x2 – x –9 + = 7(x2 – 8x
anzhelika [568]

Answer:

A) 56 . . . . . . the (negative) sum of -7 and -49

b) 112 . . . . . the product of 7 and 16

c) 16 . . . . . . the square of 8/2

8 0
4 years ago
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Need help with 7 and 8 please
iren2701 [21]

7 is “what was our opinion of the experiment and results?”

8 is “random”

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4 years ago
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What is the domain of y = log Subscript 5 Baseline x?
Marina CMI [18]

Answer:

For this case we have this function given:

y = log_5 (x)

In order to find the domain we need to find the possible values of x that the function can assume.

And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

x> 0

And we can write this in formal notation as:

D = [ X \in R | X>0]

And the best answer for this case would be:

all real numbers greater than 0

Step-by-step explanation:

For this case we have this function given:

y = log_5 (x)

In order to find the domain we need to find the possible values of x that the function can assume.

And we know that for this case the logarithm for 0 or neagtive numbers is not possible to calculate it, so then we can say that the domain for this case is:

x> 0

And we can write this in formal notation as:

D = [ X \in R | X>0]

And the best answer for this case would be:

all real numbers greater than 0

6 0
4 years ago
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T= 1,-1 u= 2, -4
Monica [59]

Answer: 3.16 units (Option C)

Step-by-step explanation:

The key to this problem is to use the distance formula, which is:

Distance = \sqrt{(x₁-x₂)²+(y₁-y₂)²}

The first point, T = (x₁,y₁), and the second point, U = (x₂,y₂).

Plugging the two points into the equation, we get:

Distance = \sqrt{(1-2)^{2}+(-1-(-4))^{2} }

The values within the parenthesis are subtracted:

Distance = \sqrt{(-1)^{2}+3^{2}  }

The values are then squared:

Distance = \sqrt{1+9}

Finally, they are added together:

Distance = \sqrt{10}

\sqrt{10} can be approximated as 3.16, so the distance between the two points is 3.16 units.

7 0
3 years ago
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