Help me figure out the answer to this 6th grade math problem please! It's on algebraic expressions.
2 answers:
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Answer:
21,500
Step-by-step explanation:
Given data ( in thousand ) in this year,
28 31 34 35 37 41 42 42 42 47 49 51 52 52 60 61 67 72 75 77,
If each data is increased by $ 3000 in the next year,
So, the data for the next year,
31 34 37 38 40 44 45 45 45 50 52 54 55 55 63 64 70 75 78 80,
Since, the data is already arranged in the ascending order,
The median is 51 which is between 50 and 52,
Thus, the lower half of the Data is, 31 34 37 38 40 44 45 45 45 50,
Having median =
= 42,
Upper half of the data is 52 54 55 55 63 64 70 75 78 80,
Having median = 63.5
Hence, the interquartile range =
= 63.5 - 42
= 21.5
That is, the Interquartile range would be 21, 500.
Answer:
Mean = 212.93
Median = 231
Mode = 231
Mid range = 192.5
(B) Yes, the time of 0 hours is very unusual. It could represent a flight that was aborted.
Step-by-step explanation:
We are given the following data set:
8, 92, 231, 189, 169, 267, 196, 381, 257, 231, 385, 330, 219, 239, 0
Formula:
a)
b)
Sorted data:
0, 8, 92, 169, 189, 196, 219, 231, 231, 239, 257, 267, 330, 381, 385
Mode is the most frequent observation in the data.
Mode = 231
It repeated 2 times.
0 is an outlier to the given dataset. Thus,
Option (B) Yes, the time of 0 hours is very unusual. It could represent a flight that was aborted.