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MaRussiya [10]
2 years ago
9

Brainlyest, plus 5 points PLEASE STEP BY STEP Evaluate x/2+5y-1.5 when x = 10 and y = 8

Mathematics
2 answers:
UkoKoshka [18]2 years ago
7 0

Answer:

43.5

Step-by-step explanation:

x ÷ 2 + 5y - 1.5

Start by replacing the x's and y's

10 ÷ 2 + (5 · 8) - 1.5

Start with parenthesis

10 ÷ 2 + 40 - 1.5

Then do the division

5 + 40 - 1.5

Then go left to right

45 - 1.5

43.5

I hope this helps!!!

frozen [14]2 years ago
4 0

Answer:

43.5

Step-by-step explanation:

x/2+5y-1.5

10/2+5×8-1.5

5+40-1.5

5+38.5

=43.5

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Answer:

2 one that's the right one

7 0
3 years ago
A line has a slope of \large \frac{5}{3}. Which of the following points could this line pass through?
kiruha [24]

Answer:well I will tell if you tell me the answer for my question

Step-by-step explanation:

6 0
3 years ago
Determine el área del siguiente rectángulo
Arte-miy333 [17]
English ⬇️

So, 8*8=64, and is expressed as 64 square feet. A square has all sides equal. So, since one side is 8 feet long the other sides also have the same length. Area of a rectangle is length multiplied by the width.

Answer?= 8

Spanish ⬇️

Entonces, 8 * 8 = 64, y se expresa como 64 pies cuadrados. Un cuadrado tiene todos los lados iguales. Entonces, dado que un lado mide 8 pies de largo, los otros lados también tienen la misma longitud. El área de un rectángulo es la longitud multiplicada por el ancho.

hola no puedo hablar español así que tuve que traducir espero que esto sea bueno y la respuesta es 8 ¡buena suerte!
5 0
3 years ago
Evaluate the expression 15g if g = 1/5.
kap26 [50]

Answer:

3

Step-by-step explanation:

15g

g=1/5

15×1/5

15/1×1/5=3

6 0
3 years ago
Read 2 more answers
Find the measure of arc DB in P<br><br>please hurry if you can​
jeyben [28]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: m \overbrace{DB}  + m \overbrace{TB}  = 180 \degree

[ linear pair ]

\qquad \tt \rightarrow \: m \overbrace{DB}  + 90 \degree  = 180 \degree

\qquad \tt \rightarrow \: m \overbrace{DB}    =  180 \degree    - 90 \degree

\qquad \tt \rightarrow \: m \overbrace{DB}    =   90 \degree

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0
2 years ago
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