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aev [14]
3 years ago
8

URGENT!

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0
V = 16, E = 37,  F = ?

F + V = E + 2

F + 16 = 37 + 2

F + 16 = 39

F = 39 - 16

F = 23 
Nataliya [291]3 years ago
3 0
F + V - E = 2....solving for F
V = 16
E = 37
just a matter of subbing and solving
F + 16 - 37 = 2
F - 21 = 2
F = 2 + 21
F = 23

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Answer: 1.5

Step-by-step explanation:

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3 years ago
Debbie is making an abstract painting with two triangles. The dimensions of the painting are shown below:
nexus9112 [7]
<span>The surface of the triangle count formula
A = b*h*1/2
A - area
b - base
c - height
</span><span>The first triangle
A</span>₁ = b₁*h = 6in * 8in *1/2= 24in²

<span>The second triangle
</span>A₂ b₂*h = 10in * 8in*1/2 = 40in²

The total area of the two triangles is 24in² + 40in² = 64 square inches

5 0
3 years ago
Read 2 more answers
Barb is making a banner that is shaped like a trapezoid the height of the banner is 24 inches the top of the banner is it 14 inc
velikii [3]

Answer:

The length of the bottom side of the banner is 17 in.

Step-by-step explanation:

Given,

Area of the Banner = 372\ in^2

Height of the Banner = 24 in

Top side of the Banner = 14 in

We have to find the length of the bottom side of the banner.

Solution,

Let the length of the bottom side of the banner be 'x'.

Since the banner is in the shape of trapezoid.

So according to the formula of area of trapezoid, which is;

Area of trapezoid =\frac{1}{2}\times \textrm{sum of parallel sides}\times \textrm{distance between them}

Here top and bottom sides are parallel and distance between them is equal to the height of the banner.

Now substituting the values, we get;

\frac{1}{2}\times24\times(x+14)=372\\\\12(x+14)=372\\\\x+14=\frac{372}{12}\\\\x+14=31\\\\x=31-14=17\ in

Hence The length of the bottom side of the banner is 17 in.

7 0
3 years ago
What does X equal how do I get it?
kvv77 [185]
X=20 because it's an equilateral triangle all the angles are 60 deg
3 0
3 years ago
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For a soccer practice, the coach set up four cones, labeled W, X, Y, and Z, to mark the edges of the rectangular field.Suppose t
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The perimeter of the field is 364 yards.

The distance between two points A(x_1, y_1) and B(x_2, y_2) is AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

WX=\sqrt{(-38-(-38))^2+(53-(-53))^2}=106 units

XY=\sqrt{(38-(-38))^2+(53-(53))^2}=76 units

Perimeter = 2 (l+w), where l is length and w is width.

Perimeter = 2(106+76)

=364 yards

Learn more about perimeter of rectangle here:

brainly.com/question/2142493?referrer=searchResults

3 0
2 years ago
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