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2 years ago

Use the function below to find f(-2) F(x)=3x

Mathematics

1 answer:

frosja888 [35]2 years ago

6 0

Answer:

Step-by-step explanation:

Using the rule of exponents

$a^{-m}$ = $\frac{1}{a^{m} }$

Then

f(- 2) = $3^{-2}$ = $\frac{1}{3^2}$ = $\frac{1}{9}$ → B

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Math is not my strong point..

Leya [2.2K]

Answer: 16 in

Explanation:

PQ/QR = PT/TS

PQ/4 = 12/3
PQ x 3 = 12 x 4 (cross multiply)
PQ x 3 = 48
PQ = 48/3
PQ = 16

6 0

2 years ago

Read 2 more answers

What is the answer for the last 2 questions

arsen [322]

A. is 20ft I believe but I don't know the other one

5 0

2 years ago

Solve the following initial-value problem: (ex+y)dx+(3+x+yey)dy=0, y(0)=1 0=

alex41 [277]

Answer:

$e^x+xy+3y+(y-1)e^y=4$

Step-by-step explanation:

Given that

$(e^x+y)dx+(3+x+ye^y)dy=0$

Here

$M=e^x+y$

$N=3+x+ye^y$

We know that

M dx + N dy=0 will be exact if

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$

$\frac{\partial N}{\partial x}=1$

it means that this is a exact equation.

$\int d\left(e^x+xy+3y+(y-1)e^y\right)=0$

Noe by integrating above equation

$e^x+xy+3y+(y-1)e^y=C$

Given that

x= 0 then y= 1

$e^0+0+3+(1-1)e^1=C$

C=4

So the our final equation will be

$e^x+xy+3y+(y-1)e^y=4$

3 0

2 years ago

Suppose y varies directly as x², and y = 160 when x = 4. Find y when x = 6.

labwork [276]

Finding the constant of proportionality :

y = kx²
160 = k(4)²
k = 10

Finding y when x = 6 :

y = 10(6)²
y = 10(36)
y = 360

The value of y is 360 when x = 6.

7 0

1 year ago

Which function is graphed below?

Masteriza [31]

Exponential Function.

$y = {a}^{x} \: \: (a > 0) \: \: (a≠1)$

Also the shown graph is a decreasing graph.

$y = {a}^{x} \: \: (0 < a < 1)$

The equation above is the equation of the graph that is shown in the picture.

8 0

2 years ago