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Misha Larkins [42]
3 years ago
12

The m1 is twice m3. The m2 is 20 more than the m3 find m4. See picture for full problem. Please and thank you!

Mathematics
1 answer:
irina1246 [14]3 years ago
8 0

Answer:

Step-by-step explanation:

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Plz help me plz give me the right answer answer I really need help ASAP do tomorrow plz help me 25points plz help I will mark be
Artyom0805 [142]

Answer:

8-d , 9-c ,and i cant see 10

Step-by-step explanation:

this is just what i know off of what i've learned

8 0
3 years ago
Solve the simultaneous equations. <br>Y=5x^2 + 4x-19<br>Y=4x+1 ​
Olegator [25]

Answer: x1=-2

x2=2

Step-by-step explanation:

5x²+4x-19=4x+1

5x²+4x-19-4x-1=0

5x²-20=0

5x²=20

x²=20/5

x²=4

x1=-√4=-2

x2=+√4=2

8 0
4 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Six times Jason
Helga [31]
Based on the given above, collection of books of Nathan and Jason can be translated into the following equations:
6J + 1/3N = 134
1/3 J + N = 31; J = Jasons and N=Nathan
Solving two equations with two unknowns simultaneously,
Jason = 21 books and Nathan = 24 books
4 0
3 years ago
Read 2 more answers
Find the HCF of 2^120-1 and 2^100-1
zlopas [31]
There may be more brilliant solution than the following, but here are my thoughts.

We make use of Euclid's algorithm to help us out.
Consider finding the hcf of A=2^(n+x)-1 and B=2^(n)-1.

If we repeated subtract B from A until the difference C is less than B (smaller number), the hcf between A and B is the same as the hcf between B and C.

For example, we would subtract 2^x times B from A, or
C=A-2^xB=2^(n+x)-2^x(2^n-1)=2^(n+x)-2^(n+x)+2^n-1=2^n-1
By the Euclidean algorithm, 
hcf(A,B)=hcf(B,C)=hcf(2^n-1,2^x-1)
If n is a multiple of x, then by repetition, we will end up with
hcf(A,B)=hcf(2^x-1,2^x-1)=2^x-1

For the given example, n=100, x=20, so
HCF(2^120-1, 2^100-1)=2^(120-100)-1=2^20-1=1048575
(since n=6x, a multiple of x).

4 0
3 years ago
The Utah Jazz scores 102 points in a recent game . The team scored some 3 point shots and 2 point shots with a total of 42 shots
makvit [3.9K]
Part aThe team scored x point shots and y point shot with a total of 42shots

Part b 42
5 0
4 years ago
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