Answer:
8-d , 9-c ,and i cant see 10
Step-by-step explanation:
this is just what i know off of what i've learned
Answer: x1=-2
x2=2
Step-by-step explanation:
5x²+4x-19=4x+1
5x²+4x-19-4x-1=0
5x²-20=0
5x²=20
x²=20/5
x²=4
x1=-√4=-2
x2=+√4=2
Based on the given above, collection of books of Nathan and Jason can be translated into the following equations:
6J + 1/3N = 134
1/3 J + N = 31; J = Jasons and N=Nathan
Solving two equations with two unknowns simultaneously,
Jason = 21 books and Nathan = 24 books
There may be more brilliant solution than the following, but here are my thoughts.
We make use of Euclid's algorithm to help us out.
Consider finding the hcf of A=2^(n+x)-1 and B=2^(n)-1.
If we repeated subtract B from A until the difference C is less than B (smaller number), the hcf between A and B is the same as the hcf between B and C.
For example, we would subtract 2^x times B from A, or
C=A-2^xB=2^(n+x)-2^x(2^n-1)=2^(n+x)-2^(n+x)+2^n-1=2^n-1
By the Euclidean algorithm,
hcf(A,B)=hcf(B,C)=hcf(2^n-1,2^x-1)
If n is a multiple of x, then by repetition, we will end up with
hcf(A,B)=hcf(2^x-1,2^x-1)=2^x-1
For the given example, n=100, x=20, so
HCF(2^120-1, 2^100-1)=2^(120-100)-1=2^20-1=1048575
(since n=6x, a multiple of x).
Part aThe team scored x point shots and y point shot with a total of 42shots
Part b 42