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3 years ago

Solve the equation:

Mathematics

1 answer:

ivann1987 [24]3 years ago

7 0

Answer:

x = √2/2

Step-by-step explanation:

Use the identity:

arcsin x + arccos x = π/2

Therefore, we can rewrite this as:

arcsin x (π/2 − arcsin x) = π²/16

If we substitute y = arcsin x:

y (π/2 − y) = π²/16

π/2 y − y² = π²/16

0 = y² − π/2 y + π²/16

0 = 16y² − 8π y + π²

0 = (4y − π)²

y = π/4

Substituting back:

arcsin x = π/4

x = sin(π/4)

x = √2/2

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marshall27 [118]

Step-by-step explanation:

as in the other problem, the table describes mutually exclusive attributes.

so, we can simply sum the numbers up to get the total number of students :

3+9+2+16 = 30 students.

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2 years ago

I’m not sure I understand this equation

AURORKA [14]

Answer:

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Step-by-step explanation:

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3 years ago

The population of New Jersey is

MissTica

The answer is: ( in 9 years )

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2 years ago

Find the equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation 3/2x-2y=-

kondaur [170]

The equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation $\frac{3}{2}x - 2y = \frac{-17}{2}$ is:

$y = \frac{3}{4}x - \frac{15}{4}$

<h3>Solution:</h3>

Given that line that passes through the point (1, -3) and that is parallel to the line with the equation $\frac{3}{2}x - 2y = \frac{-17}{2}$

We have to find equation of line

The slope intercept form is given as:

y = mx + c

Where "m" is the slope of line and "c" is the y-intercept

Let us first find slope of line containing equation $\frac{3}{2}x - 2y = \frac{-17}{2}$

$\frac{3}{2}x - 2y = \frac{-17}{2}$

Rearrange the above equation into slope intercept form

$\frac{3x}{2} + \frac{17}{2} = 2y\\\\y = \frac{3x}{4} + \frac{17}{4}$

On comparing the above equation with slope intercept form y = mx + c,

$m = \frac{3}{4}$

So the slope of line containing equation $\frac{3}{2}x - 2y = \frac{-17}{2}$ is $m = \frac{3}{4}$

We know that slopes of parallel lines are equal

So the slope of line parallel to line having above equation is also $m = \frac{3}{4}$

Now let us find the equation of line having slope m = 3/4 and passes through point (1 , -3)

Substitute $m = \frac{3}{4}$ and (x, y) = (1 , -3) in slope intercept form

y = mx + c

$-3 = \frac{3}{4}(1) + c\\\\c = -3 - \frac{3}{4}\\\\c = \frac{-15}{4}$

Thus the required equation of line is:

substitute $m = \frac{3}{4}$ and $c = \frac{-15}{4}$ in slope intercept form

$y = \frac{3}{4}x + \frac{-15}{4}\\\\y =\frac{3}{4}x - \frac{15}{4}$

Thus the equation of line is found out

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2 years ago

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Agata [3.3K]

Answer:

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Step-by-step explanation:

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3 years ago