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2 years ago

Factorise the expression:21x+3xy+6x²

Mathematics

2 answers:

krok68 [10]2 years ago

8 0

Answer:

3x(7+y+2x)

Step-by-step explanation:

1) Find the Greatest Common Factor (GCF).

A. What is the largest number that divides evenly into 21x, 3xy, and 6x²?

It is 3.

B. What is the highest degree of x that divides evenly into 21x, 3xy , and 6x²?

It is x.

C. hat is the highest degree of y that divides evenly into 21x, 3xy, and 6x²?

It is 1, since y is not in every term.

D. Multiplying the results above,

The GCF is 3x.

2) Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

$3x(\frac{21x}{3x} +\frac{3xy}{3x} +\frac{6x^{2} }{3x} )$

3) Simplify each term in parentheses.

$3x(7+y+2x)$

MArishka [77]2 years ago

5 0

$21x+3xy+6x^{2} = 6x^{2}+3xy+21x=3x.2x +3xy+3x.7 =3x.(2x+y+7)$

ok done. Thank to me :>

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3 years ago

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marissa [1.9K]

Option D: $(f\times g)(x)=12 x^{2}-48 x+21$ ; all real numbers.

Explanation:

Given that the functions are $f(x)=-2 x+7$ and $g(x)=-6 x+3$

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The value of $(f\times g)(x)$ :

The value of $(f\times g)(x)$ can be determined by multiplying the two functions.

Thus, we have,

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Thus, the value of $(f\times g)(x)$ is $(f\times g)(x)=12 x^{2}-48 x+21$

Domain:

We need to determine the domain of the function $(f\times g)(x)$

The domain of the function is the set of all independent x - values for which the function is real and well defined.

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Factorise the expression:21x+3xy+6x²​

Factorise the expression:21x+3xy+6x²