Question

Factorise the expression:21x+3xy+6x²​

Answer 1

Answer:

3x(7+y+2x)

Step-by-step explanation:

1) Find the Greatest Common Factor (GCF).

A. What is the largest number that divides evenly into 21x, 3xy, and 6x²?

It is 3.

B. What is the highest degree of x that divides evenly into 21x, 3xy , and 6x²?

It is x.

C. hat is the highest degree of y that divides evenly into 21x, 3xy, and 6x²?

It is 1, since y is not in every term.

D. Multiplying the results above,

The GCF is 3x.

2) Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

$3x(\frac{21x}{3x} +\frac{3xy}{3x} +\frac{6x^{2} }{3x} )$

3)  Simplify each term in parentheses.

$3x(7+y+2x)$

Answer 2

$21x+3xy+6x^{2} = 6x^{2}+3xy+21x=3x.2x +3xy+3x.7 =3x.(2x+y+7)$

ok done. Thank to me :>