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3 years ago

Tell whether the two rates form a proportion.

Mathematics

1 answer:

ANEK [815]3 years ago

5 0

The two rates 12 players from 21 teams; 15 players from 24 teams do not form a proportion

<h3>How to solve proportion</h3>

Given:

12 players from 21 teams

Ratio of players to team = 12 : 21

= 12/21

= 4 / 7

= 4 : 7

15 players from 24 teams

Ratio of players to team = 15 : 24

= 15 / 24

= 5 / 8

= 5 : 8

Learn more about proportion:

brainly.com/question/1781657

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The base of an isosceles triangle is 2 cm. The perimeter of the triangle is 10 cm.

cluponka [151]

Answer and Step-by-step explanation:

$Greetings!$

$Let's~solve~your~question!$

$To~find~the~length~of~equal~sides~of~an~isosceles~triangle,~we~use~the~following\\formula.$

$\boxed{~P=2a+b~}$

$Now,~solving~for~``a":$

$P=\frac{P}{2} -\frac{b}{2}$

$=\frac{10}{2}-\frac{2}{2}$

$=5-1$

$=4$

$Thus,~each~equal~sides~of~an~isosceles~triangle~is~4cm.$

$Hope~my~answer~helps~and~have~a~blessed~day~ahead!$

$-Isabelle~Williams$

8 0

3 years ago

What is the volume of a sphere with a diameter of 5.4 ft, rounded to the nearest tenth of a cubic foot?

Lelechka [254]

Answer:

82.4 ft^3

Step-by-step explanation:

Diameter=5.4ft

Radius=diameter/2

=5.4ft/2

=2.7ft

π=3.14

Volume of a sphere=4/3πr^3

=4/3×3.14×2.7^3

=4/3×3.14×19.683

=4/3×61.80462

=247.21848/3

=82.40616

Approximately

82.4 ft^3

7 0

3 years ago

HELP ME I CANT SEE ANY ASNWERS

oee [108]

Answer:

same PLS HElp

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is 3/4 - 9/12. plz help

vova2212 [387]

3 divided by 4 subtract 9 divided by 12 equals 0. Hope this helps

8 0

4 years ago

Read 2 more answers

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

3 years ago