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SVETLANKA909090 [29]
3 years ago
11

How are gas particles arranged in a container?

Physics
2 answers:
omeli [17]3 years ago
5 0
The answer is loosely arranged
joja [24]3 years ago
4 0

Answer:

3. Tightly Packed

Explanation:

Hope this helps

I learned this

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A spring has a spring constant of 450 N/m. How much must this spring be stretched to store 49 J of potential energy?
statuscvo [17]

Answer:

W = 1/2 K x^2

x^2 = 2 * W / K = 2 * 49 J / (N/m)  = .218 / m^2

x =  .467 m

5 0
3 years ago
Which one is a element??​
MaRussiya [10]

Answer:

A.) Carbon

Explanation:

Carbon is an element on the periodic table.

it has the symbol C, and is found in almost every single thing!

4 0
3 years ago
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A responder can protect himself/herself from radiation by using shielding as a response action. What materials are best for prot
Irina-Kira [14]

Answer:

Few millimeter thick aluminium, water, wood, acrylic glass or plastic.

Explanation:

The materials that are best for protection against beta particles are few millimeter thickness of aluminium, but for the high energy beta-particles radiations the low atomic mass materials such as plastic, wood, water and acrylic glass can be used.

These materials can also be used in personal protective equipment which includes all the clothing that can be worn to prevent any injury or illness due to the exposure to radiation.

3 0
3 years ago
A loop with a break in it that prevents current from flowing is called a(n)_______<br> circuit.
Annette [7]

Answer:

an open circuit

Explanation:

7 0
4 years ago
A well-insulated electric water heater warms 131 kg of water from 20.0°C to 51.0°C in 31.0 min. Find the resistance (in Ω) of it
Nookie1986 [14]

Answer:

Explanation:

Heat required to warm the water from 20 degree to 51 degree

= mct

= 131 x 4150 x ( 51 - 20 )

= 16853150 J

Power of heating element

= v² /R

Heat generated in 31 min

= (v² / r ) x 31 x 60 = 16853150

r = (240 x 240 x 31 x 60) / 16853150

6.35 ohm

In this case heat required will change so time will also change

Heat required =

131 x 4150 x ( 100-51  )

= 26638850 J

If time required be t hour

Energy consumed

Power x time

=  (v² / r ) x t  x 60 = 26638850

t  = 26638850 x 6.35 / (240 x 240 x 60 )

= 48.95 h

Heat required to evaporate water at 100 degree

= mass x latent heat

= 131 x 2260000

= 296060000 J

Total heat required

= 296060000 + 26638850 + 16853150

= 339552000 J

time required = 339552000 x 6.35 / (240 x 240 x 60 )

= 623.88 h .

3 0
3 years ago
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