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2 years ago

A raindrop falls to the ground from a rain cloud at an altitude of 3000 meters.

Physics

1 answer:

shutvik [7]2 years ago

8 0

Assuming the raindrop was stationary relative to the vertical distance to the ground at the start:

D=0.5at where d is distance, a is acceleration and t is time

D is 300 meters

a is 9.8 meter/sec squared

Solve for t in seconds

t = 61.2 seconds

v=at where v is velocity

a is 9.8 meters per second squared

t is 61.2 seconds

solve for v

v = 600 meters per second.

If it had an initial vertical velocity (v0) at the start :

d= 0.5at+v0t

and

v=at+v0

You might be interested in

. When two speakers play different sounds with a constant frequency, beats are heard with a frequency of 5 Hz. If the frequency

morpeh [17]

The beat frequency is the concept required to develop this process. The phenomenon is generated when you have two waves but their frequencies do not differ greatly. So the beat frequency will be the difference between those two waves. For this case we have the difference and one of the waves, therefore,

$F_b = |F_1-F_2|$

Our values are given as,

$F_b = 5Hz$

$F_1 = 1050Hz$

Using the formula of the frequency I will have,

$F_b = |F_1-F_2|$

Replacing we have,

$5 = |1050-F_2|$

$F_2 = 1050 \pm 5$

$F_2 = 1045,1055 Hz$

The possible values are two: 1045Hz and 1055Hz

3 0

3 years ago

Please help 25 points!

cricket20 [7]

<h3>2 Answers:</h3>

a) Velocity is a vector quantity

e) Velocity is a speed with direction

=================================================

Explanation:

If we know the velocity of an object, then we know how fast it's going (speed) and where it's going (direction). It is a vector because the direction of the vector determines the direction, and the length of the vector (aka magnitude) determines the speed. So in a sense we've built in two facts of data into one visual.

An example of velocity: 10 miles per hour north. Here we have the speed of 10 mph and the direction north.

-------------------

Extra info:

Choice B contradicts choice A, so we can cross choice B off the list.
Choice C is false because speed is a scalar, or single quantity, and not a vector. As mentioned earlier, speed is a part of velocity, but they aren't the same exact thing.
Choice D is false because the velocity does not account for net force. We don't have any force information built into the velocity.

8 0

3 years ago

Read 2 more answers

A 15.5 kg mass vibrates in simple harmonic motion with a frequency of 9.73 Hz. It has a maximum displacement from equilibrium of

algol [13]

Answer:

12.14 cm

Explanation:

mass, m = 15.5 kg

frequency, f = 9.73 Hz

maximum amplitude, A = 14.6 cm

t = 1.25 s

The equation of the simple harmonic motion

y = A Sin ωt

y = A Sin (2 x π x f x t)

put, t = 1.25 s, A = 14.6 cm, f = 9.73 Hz

y = 14.6 Sin ( 2 x 3.14 x 9.73 x 1.25)

y = 14.6 Sin 76.38

y = 12.14 cm

Thus, the displacement of the particle from the equilibrium position is 12.14 cm.

6 0

3 years ago

The initial kinetic energy imparted to a 0.020 kg bullet is 1200 J. (a) Assuming it

Lilit [14]

Answer:

(a) Power= 207.97 kW

(b) Range= 5768.6 meter

Explanation:

Given,

Mass of bullet, $m=0.02 kg$

Kinetic energy imparted, $K=1200 J$

Length of rifle barrel, $d=1 m$

(a)

Let the speed of bullet when it leaves the barrel is $v$ .

Kinetic energy, $K=\frac{1}{2} mv^{2}$

$v=\sqrt{\frac{2K}{m} }$

$=\sqrt{\frac{2\times1200}{0.02} }$

$=346.4m/s$

Initial speed of bullet, $u=0$

The average speed in the barrel, $v_a_v_g=\frac{u+v}{2}$

$=\frac{0+346.4}{2} \\=173.2 m/s$

Time taken by bullet to cross the barrel, $t=\frac{d}{v}$

$=\frac{1}{173.2}\\ =0.00577 second$

Power, $P_a_v_g=\frac{W}{t}$

$=\frac{1200}{0.00577} \\=207.97kW$

(b)

In projectile motion,

Maximum height, $H_m=\frac{v^2\sin^2\theta}{2g} \\$

Range, $R=\frac{v^2\sin2\theta}{g}$

given that, $H_m=R$

then, $\frac{v^2\sin^2\theta}{2g}=\frac{v^2\sin2\theta}{g}\\\sin^2\theta=2\sin\theta\cos\theta\\\\\tan\theta=4\\\theta=\tan^-^14\\\theta=75.96^0\\R=\frac{v^2\sin2\theta}{g}\\=\frac{346.4^2\times\sin(2\times75.96)}{9.8}\\5768.6 meter$

5 0

2 years ago

A jet fighter flying at 300 m/s (just below the speed of sound) makes a turn of radius 1.85 km. (a) what is its centripetal acce

777dan777 [17]

centripetal acceleration can be determined using the following equation;
a = v² / r
a= centripetal acceleration
v = velocity
r = radius
substituting the values in the equation,
a = (300 m/s)*(300m/s) / (1.85 *1000) m
= 48.64 ms-²

7 0

3 years ago