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2 years ago

Directions: Simplify these problems by combining like terms.

2 answers:

4 0

Answer: (1)=5s-6 (2)=11+6 (3)=42r (4)=4-4q+40r (5)=?? (6)=101+102x (7)=17a2-11a (8)=29T (9)=r+3s+2rs (10)=51pt-3p+4t (11)=17x2 (13)=18q+5 (14)=4K (15)=249x

Step-by-step explanation: math.

Verdich [7]2 years ago

3 0

Answer:

6s + 2s - 3s - 6:

5s-6

10t - 4t -6 + 5t:

11t-6

18r + 18r + 9r - 3r:

42r

20 - 4q + 40r - 16:

-4q+40r+4

17st - 16s + t:

17st-16s+t

. 101+101x - x:

101+100x

16a2 - 14a + a2 - 3a:

14 ato the power of 2- 17a

14t + 14t + t:

29t

r + s + rs + s + rs + s:

r+2rs+3s

54 pt - 3p + 4t - 3pt:

51pt-3p+4t

i dont know 11

101c - 5c +4c:

100c

12q - 4 + 10q - 4q +9:

18q+5

21k - 20k + 3k:

181x + 91x - 23x:

249x

Step-by-step explanation:

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4 years ago

HELP. Multiply the polynomials and simplify the answer. Show your work.

Aliun [14]

Answer:

Part 1)

$=12a^5-6a^4-5a^3-24a^2+12a-7$

Part 2)

$(2x^3-10x^2+5x+14)\div(x-2)=2x^2-6x-7$

Step-by-step explanation:

Part 1)

We would like to multiply:

$(3a^3-2a-7)(4a^2-2a+1)$

Distribute each term from the first group into the second group. So:

$=3a^3(4a^2-2a+1)-2a(4a^2-2a+1)-7(4a^2-2a+1)$

Distribute further:

$=(12a^5-6a^4+3a^3)+(-8a^3+4a^2-2a)+(-28a^2+14a-7)$

Combine like terms:

$=(12a^5)+(-6a^4)+(3a^3-8a^3)+(-28a^2+4a^2)+(-2a+14a)+(-7)$

Simplify:

$=12a^5-6a^4-5a^3-24a^2+12a-7$

Part 2)

We would like to divide:

$(2x^3-10x^2+5x+14)\div(x-2)$

Using long division.

Please refer to the attached document.

For the first step, x goes into 2x³ 2x² times. Hence, we multiply our divisor by 2x².

Next, x goes into -6x^2 -6x times. Hence, we multiply our divisor by -6x.

Finally, x goes into -7x -7 times. So, we multiply our divisor by -7 and we simplify.

Therefore:

$(2x^3-10x^2+5x+14)\div(x-2)=2x^2-6x-7$

7 0

3 years ago

Find the equation of the line tangent to the graph of

garik1379 [7]

Answer:

$\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}$

Step-by-step explanation:

We want to find the equation of the line tangent to the graph of:

$\displaystyle y=\sin^{-1}\big(\frac{x}{5}\big)\text{ at } x=\frac{5}{2}$

So, we will find the derivative of our equation first. Applying the chain rule, we acquire that:

$\displaystyle y^\prime=\frac{1}{\sqrt{1-(\frac{x}{5})^2}}\cdot\frac{1}{5}$

Simplify:

$\displaystyle y^\prime=\frac{1}{5\sqrt{1-\frac{x^2}{25}}}$

We can factor out the denominator within the square root:

$\displaystyle y^\prime =\frac{1}{5\sqrt{\frac{1}{25}\big(25-x^2)}}$

Simplify:

$\displaystyle y^\prime=\frac{1}{\sqrt{25-x^2}}$

So, we can find the slope of the tangent line at <em>x</em> = 5/2. By substitution:

$\displaystyle y^\prime=\frac{1}{\sqrt{25-(5/2)^2}}$

Evaluate:

$\displaystyle y^\prime=\frac{1}{\sqrt{75/4}}=\frac{1}{\frac{5\sqrt{3}}{2}}=\frac{2\sqrt{3}}{15}$

We will also need the point at <em>x</em> = 5/2. Using our original equation, we acquire that:

$\displaystyle y=\sin^{-1}(\frac{1}{2})=\frac{\pi}{6}$

So, a point is (5/2, π/6).

Finally, by using the point-slope form, we can write:

$\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}(x-\frac{5}{2})$

Distribute:

$\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}x+\frac{-\sqrt{3}}{3}$

Isolate. Hence, our equation is:

$\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}$

7 0

3 years ago

Can someone please answer this for me please??

klio [65]

Answer:

15/16

Step-by-step explanation:

Using the order of operations, we need to multiply in the parentheses first...

3/5*25/24=75/120, which simplifies to 5/8.

Next, we need to divide 5/8 by 2/3. To divide, we can actually multiply by the reciprocal, which is flipping the fraction that you are dividing by. In this case, we need to multiply 5/8 by the reciprocal of 2/3. The reciprocal of 2/3 is 3/2, so we need to multiply 5/8 by 3/2.

5/8*3/2=15/16

This is the final answer!

I hope this helped you out!! Have an amazing day φ(゜▽゜*)♪

6 0

3 years ago