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dmitriy555 [2]
2 years ago
5

-10 , -6 , -2 , 2 , _____ this sequence in an A.P.? why?

Mathematics
1 answer:
faust18 [17]2 years ago
6 0
The answer for this is negative 4
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What is (1.2)to the power of 4
Cloud [144]

Answer:2.0736

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HELP, GIVING 55 POINTS IF YOU ANSWER (08.03/08.05 MC) A pair of equations is shown below: y = 3x − 5 y = 6x − 8 Part A: E
Andrew [12]

Answer:

  A. (1, -2)

  B. the lines intersect at the solution point: (1, -2).

Step-by-step explanation:

A. The equations can be solve by substitution by using the y-expression provided by one of them to substitute for y in the other.

This gives ...

  3x -5 = 6x -8

Adding 8-3x to both sides, we get ...

  3 = 3x

Dividing both sides by 3 gives ...

  1 = x

Substituting this value into the first equation, we can find y:

  y = 3(1) -5 = -2

The solution is (x, y) = (1, -2).

__

B. The lines intersect at the solution point, the point that satisfies both equations simultaneously. That point is (1, -2).

8 0
4 years ago
The first five terms of a linear sequence are given below. 7 , 12 , 17, 22 , 27 , ... What is the next term of the sequence?
Norma-Jean [14]

Answer:

<h2>32</h2>

Step-by-step explanation:

a_1=7\\a_2=7+5=12\\a_3=12+5=17\\a_4=17+5=22\\a_5=22+5=27\\\\a_6=27+5=32\\a_7=32+5=37\\a_8=37+5=42\\a_9=42+5=47\\\vdots

8 0
3 years ago
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
-1.32+x=1 <br> -1 -1<br><br> Not sure about this??
Ipatiy [6.2K]

Answer:

x=2.32

Step-by-step explanation:

-1.32+x=1

add 1.32 to both sides

1.32 cancels itself out

so you are left with x=2.32

7 0
3 years ago
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