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Yuliya22 [10]
2 years ago
10

Root 2×root5

a1" title=" \sqrt{2 \times \sqrt{5 = } } " alt=" \sqrt{2 \times \sqrt{5 = } } " align="absmiddle" class="latex-formula">how much???
​​​
Mathematics
1 answer:
Maurinko [17]2 years ago
3 0
<h2>Answer:</h2>

\sqrt[4]{20 {x}^{2} }

<h2>Step-by-step explanation:</h2>

\sqrt{2x \sqrt{5} } \\  \\  \sqrt{2 \sqrt{5x} }  \\  \\  \sqrt{ \sqrt{(2 {x}^{2} )} \sqrt{5}  }  \\  \\  \sqrt{ \sqrt{4 {x}^{2} }  \times 5}  \\  \\  \sqrt{ \sqrt{20 {x}^{2} } }  \\  \\  \sqrt[4]{20 {x}^{2} }

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Help me
Rashid [163]
The answer to your question would be B because you divide 10 by 3.5 to get 3, then you would divide 12 by 3 to get 4. Multiply them together to get 14
4 0
3 years ago
Please help me with this:
Katen [24]

Answer:

She used 22 paper fans, 66 balloons, and 32 streamers.

Step-by-step explanation:

In order to solve this problem, we need to find out the value of the paper fans. Because we need to find out the balloon amount, which is 3 times as much. The amount of streamers is 12 fewer than two times. We can't find it out just yet since we don't know the value of the paper fans. To find it out:

First, let's call the amount of paper fan as "x".

Then, we need to find out the amount of balloons. It is 3 times x. Which is the same as 3x.

The equation is now x + 3x + (?) = 120

We need to find out the amount of the (?).

So, to do that, it says the value is 12 fewer than 2 times the value of x. (x, because it is the amount of paper fans.)

It should be 2x-12.

Now, the equation is x+3x+2x-12=120.

Once we solve it, we know "x" is 22.

Now, we can multiply 3 by 22. Which is 66.

Then we can multiply 22 by 2, which is 44, and subtract 12, which is 32.

To double check, 22 + 44 + 32 = 120.

That's your answer!

5 0
3 years ago
Read 2 more answers
What is 32.330 + 23.559
Molodets [167]
I hope this helps you

5 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=%7Cx-6%7C" id="TexFormula1" title="|x-6|" alt="|x-6|" align="absmiddle" class="latex-f
Fofino [41]

9514 1404 393

Answer:

  x - 6

Step-by-step explanation:

For values of x greater than or equal to 6, the difference x-6 is non-negative, so the absolute value function does nothing. The value is ...

  x -6

7 0
3 years ago
Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
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