Answer:
Step 1: Simplify both sides of the equation.
2−8x=10
2+−8x=10
−8x+2=10
Step 2: Subtract 2 from both sides.
−8x+2−2=10−2
−8x=8
Step 3: Divide both sides by -8.
−8x ÷ −8
=
8 ÷ −8
x=−1
Answer:
x=−1
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Since it's not mentioned I assume the Event of tossing a die twice are done simultaneously.
1- What is the theoretical probability that a coin toss results in two heads showing? I guess you mean: The theoretical probability of tossing 2 heads in 2 flips, if so P(1st Head) = 1/2 AND P(2nd Head) = 1/2, then the probability of getting 2 heads simultaneously is P(1st Head AND 2nd Head) = 1/2 x 1/2 = 1/4
2- What is the experimental probability that a coin toss results in two heads showing? In this case, I suggest that you toss a coin several times until 2 heads appear and then you calculate P: Assuming you get 2 heads (out of 10toss), the P(H) =2/10
3- What is the experimental probability that a coin toss results in two tails showing? Same logic as the previous one
4- What is the theoretical probability that a coin toss results in one head and one tail showing? If you get one Head, P(H) =1/2 and if you want a tail in the 2nd toss P(1/2). So P(one Head AND one tail) = 1/2 x 1/2 = 1/4
5- What is the experimental probability that a coin toss results in one head and one tail showing? Same as 3- or 4-
Answer:
x is all real numbers
Step-by-step explanation:
2(y-6)=3(y-4)-y
Distribute
2y - 12 = 3y-12 -y
Combine like terms
2y -12 = 2y -12
Subtract 2y from each side
2y-12-2y = 2y-12 -2y
-12 =-12
This is always true so there are infinite solutions
x is all real numbers
F + V - E = 2....solving for F
V = 16
E = 37
just a matter of subbing and solving
F + 16 - 37 = 2
F - 21 = 2
F = 2 + 21
F = 23
