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Aleonysh [2.5K]
2 years ago
8

Quadrilateral WXYZ has the coordinates W(b, b), X(4b, b), Y(3b, 0), and Z(0, 0).

Mathematics
1 answer:
AnnZ [28]2 years ago
7 0

The length of side WX in Quadrilateral WXYZ is 3b units.

<h3>Coordinate plane</h3>

The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:

AB=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Given the coordinates W(b, b), X(4b, b), Y(3b, 0), and Z(0, 0). The length of WX is:

WX=\sqrt{(b-b)^2+(4b-b)^2}=3b

The length of side WX in Quadrilateral WXYZ is 3b units.

Find out more on coordinate plane at: brainly.com/question/26100648

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lesya692 [45]
<span> -14x + 11y = 23
+2(7x - 3y = 37)
----------------------
   0 + 5y = 97
y  = 97/5
y = 19.4

7x - 3(19.4) = 37
7x - 58.2 = 37
7x = 37 + 58.2
7x = 95.2
x = 95.2/7
x = 13.6

Check

-14(13.6) + 11(19.4) = 23
-190.4 + 213.4 = 23
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Solve.
bixtya [17]

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x = -b ± \frac{\sqrt{{b}^{2} - 4ac}}{2a}

-6 ± \frac{\sqrt{{6}^{2} - 4(1)(-3)}}{2(1)} =   -6 ± \frac{\sqrt{36 + 12}}{2} = -6 ± \frac{\sqrt{48}}{2} \\ \\ -3 ± 2\sqrt{3}

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½[4√3] = 2√3

Then attach half of -6 to it as well [-3]:

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I am joyous to assist you anytime.

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