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shtirl [24]
2 years ago
15

Help me please It about linear equations

Mathematics
1 answer:
marin [14]2 years ago
5 0

Answer:

Hours:         Elevation:

0                  3000

2                  2000

5                  500

Step-by-step explanation:

Time is always placed on the x (horizontal) axis, and the dependent variable on the y. Just find the number given and find the corresponding value to go with it! Hope this helps :)

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Which of the following is the solution to |x-13|<18
serious [3.7K]

Rewrite the inequality without the absolute value

-18 < x - 13 < 18

Add 13 to the whole equation

-18 + 13 < x < 18 + 13

Simplify

<u>-5 < x < 31</u>

3 0
3 years ago
Read 2 more answers
9⋅(3+5)+8÷2
Slav-nsk [51]

Answer:

76

Step-by-step explanation:

8 0
2 years ago
What is the modulus of |9+40i|?
Talja [164]

Answer:

41

Step-by-step explanation:

We know that complex numbers are a combination of real and imaginary numbers

Real part is x and imaginary part y is multiplied by i, square root of -1

Modulus of x+iy = \sqrt{x^2+y^2}

Here instead of x and y are given 9 and 40

i.e. 9+40i

Hence to find modulus we square the coefficients add them and then find square root

|9+49i| =\sqrt{9^2+40^2} =\sqrt{1681}

By long division method we find that

|9+40i| =41


6 0
2 years ago
Read 2 more answers
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
2 years ago
Which conic's equation has 2 squares with the same signs and different leading coefficients?
Romashka [77]

We want to see which is the conic equation that has 2 squares with the same sign and different leading coefficients.

We will see that it is the equation of the ellipse.

Now let's see why that is the correct answer.

The general conic equation is of the form:

A*(x - a)^2 + B*(x - b)^2 = R^2

Where A and B are the leading coefficients, (a, b) is the center of the figure, and R is the average radius of the figure.

For example, if A = B, this would be the equation of a circle, but we must have two different leading coefficients.

If we write:

A = 1/C

B = 1/K

(both are positive, because "it has two squares with the same signs").

Then we get the equation:

\frac{ (x - a)^2}{C} + \frac{(x - b)^2}{K} = R^2

We get the equation we wanted.

The same sign in both square parts and different leading coefficients.

The above equation is the general equation of an ellipse.

If you want to learn more, you can read:

brainly.com/question/10311514

7 0
2 years ago
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