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Elanso [62]
3 years ago
11

The circumference of a circle is 18.84 yards what is the circles diameter

Mathematics
1 answer:
Alika [10]3 years ago
4 0

Answer:

6cm

Step-by-step explanation:

to find the diameter of a circle whose  circumference is = 18 .84

the formula for finding the circumference of a crcle = πd

18.84 = πd

note π = 22/7 or 3.14

so,

18. 84 = 3.14 × d

divide both sides by 3.14

18.84/3.14 = 3.14d/3.14

6cm = d

therefore the diameter of the circle whose circumference is 18.84 is equal to 6cm

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What is the value of x in: 4x+3y=12 and 2x-3y=-30 *
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Answer:

The value would be

Step-by-step explanation:

What is the value of x in: 4x+3y=12 and 2x-3y=-30 *

4x + 3y

The answer is x = 2 - 3y = 4

3y = 30

So 2x + 3y = 12 is

X = 3 - 3y/4

2x - 3y = 30

X = 15 + 3y/2

Hope it help : ) Please Rate it for me!

Have a Great Day and Winter Break!

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Find the slope of the line containing the pair of the points. (-10,9) and (-6,-9)
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-9/4

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What is the area of a square if one side is 25 feet long?
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the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
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Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
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