(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
multiply it and you can change it done ez as pie
Step-by-step explanation:
Simplify. Combine like terms
12x - 9x = 3x
7 - 15 = -8
3x - 8 is your answer
hope this helps
Answer:3/9
Step-by-step explanation:
"Prime Factorization" is finding which prime numbers multiply together to make the original number.
Because prime numbers are all whole numbers (no decimals), there is no way to get a product of prime numbers that is a decimal like 4.8.
In other words, because 4.8 is not a positive whole number, you can't find its prime factorization.
