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Delicious77 [7]

4 years ago

15

Why is it important to understand the behavior of light when designing and building any type of structure, such as a house, scho

ol, store, hospital or office building?

1 answer:

geniusboy [140]4 years ago

5 0

Answer:

because it is important

You might be interested in

Si se aplic una fuerza de 150N en un área de de 0.4m2¿cual será la preciosa ejercida?

natali 33 [55]

Answer:

P = 375 Pa

Explanation:

The question says that,"If a force of 150N was applied in an area of 0.4m², what will be the precious exerted?"

We have,

Force, F = 150 N

Area, A = 0.4m²

We need to find the pressure exerted. We know that,

Pressure = forece/area

So,

$P=\dfrac{150\ N}{0.4\ m^2}\\\\P=375\ Pa$

So, the required pressure is equal to 375 pa.

7 0

3 years ago

How many coulombs of positive charge are there in 3.60 kg of plutonium, given its atomic mass is 244 and that each plutonium ato

PtichkaEL [24]

1 mole of plutonium = 244 gm

3.6 kg of plutonium = 3.6 × 1000 = 3600 gm

Number of moles = 3600 ÷ 244 = 14.754 moles

One moles of plutonium contains protons = $6.023 \times {10}^{23} \times 94$

Total number of protons in 14.754 moles = $6.023 \times {10}^{23} \times 94 \times 14.754$

Total number of protons in 14.754 moles = $8353.15 \times {10}^{23}$

Total Positive charge = $8353.15 \times {10}^{23} \times 1.6 \times {10}^{-19}$

Total positive charge = $13365.04 \times {10}^{4}$ C

3 0

4 years ago

Reviewing old tests and quizzes will not help you determine what will be on a test because teachers don’t like to give students

kifflom [539]

Answer:

False

Explanation:

5 0

4 years ago

Read 2 more answers

An object is placed 96.5 cm from a glass lens (n = 1.51) with one concave surface of radius 24 cm and one convex surface of radi

poizon [28]

Answer:

image is vertical at distance -203.62 cm

magnification is 2.110

Explanation:

given data

n = 1.51

distance u = 96.5 cm

concave radius r1 = 24 cm

convex radius r2 = 19.1 cm

to find out

final image distance and magnification

solution

we will apply here lens formula to find focal length f

1/f = n-1 ( 1/r1 - 1/r2) .......................1

put here all value

1/f = 1.51 -1 ( -1/24 + 1/19.1)

f = 183.43

so from lens formula

1/f = 1/v + 1/u .............................2

put here all value and find v

1/183.43 = 1/v + 1/96.5

so

v = −203.62 cm

so here image is vertical at distance -203.62 cm

and

magnification are = -v /u

magnification = 203.62 / 96.5

magnification is 2.110

3 0

4 years ago

A hollow cylindrical (inner radius = 1.0 mm, outer radius = 3.0 mm) conductor carries a current of 80 A parallel to its axis. Th

Pavlova-9 [17]

Answer:

The magnetic field is $B = 3 mT$

Explanation:

From the question we are told that

The inner radius is $r_i = 1.00 mm =1*10^{-3} \ m$

The outer radius is $r_2 = 3.00 \ mm = 3.0 *10^{-3} \ m$

The distance from the axis of the conductor is $d =2.0 \ mm = 2.0 *10^{-3} \ m$

The current carried by the conductor is $I = 80 A$

According to Ampere's circuital law , the magnetic field at a point that is $r_3$ from the axis of the conductor

$B = \frac{\mu_oI}{2 \pi d } [\frac{d - r_1}{r_2 -r_1} ]$

Where $\mu_o$ is the permeability of free space with a value of $\mu_o = 4 \pi *10^{-7} N/A^2$

substituting values

$B = \frac{(4 \pi *10^{-7})(80)}{2 * 3.142 * 2 *10^{=3} } [\frac{(2^2 - 1 ^2 )*10^{-3}}{(3^2 - 1^2) *10^{-3}} ]$

$B = 3 mT$

5 0

4 years ago