The prefix of a unit could give you a hint on its extent with respect to the base unit. In this case, the base unit is money in terms of dollars. When you say kilodollars, that would be 1,000 times as large as a dollar. Hence,
33,200 dollars * 1 kilodollar/ 1,000 dollars = 33.2 kilodollars
When you say megadollars, that would be a million times as large as a dollar. Hence,
33,200 dollars * 1 megadollar/1,000,000 dollars = 0.0332 megadollars
Answer:
40 m/s.
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 60 m/s
Height (h) = 100 m
Acceleration due to gravity (g) = 10 m/s²
Final velocity (v) =?
The velocity at height 100 m can be obtained as follow:
v² = u² – 2gh (since the ball is going against gravity)
v² = 60² – (2 × 10 × 100)
v² = 3600 – 2000
v² = 1600
Take the square root of both side
v = √1600
v = 40 m/s
Thus, velocity at height 100 m is 40 m/s
Answer: 339.148N
Explanation:
Data
Time (t) = 47s
U = 0m/s
V = 9.5m/s
Mass of B = 540kg
Frictional force on B = 230N
Both boats are connected so if A moves, B moves too.
Acceleration of boat A =?
Using equation of motion,
V = u + at
9.5 = 0 + a*47
a = 9.5 / 47
a = 0.2021 m/s²
The force required to accelerate boat B since it's the same force moving both boats =?
F = Mass * acceleration
F = 540 * 0.2021 = 109.14N
A frictional force of 230N exists on boat B
Total force (Tension) = frictional force + normal force = (109.15 + 230)N = 339.148N
Answer:
0.557 s
Explanation:
Given:
v₀ = 5.46 m/s
v = 0 m/s
a = -9.8 m/s²
Find: t
v = at + v₀
0 m/s = (-9.8 m/s²) t + 5.46 m/s
t = 0.557 s
