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Maurinko [17]
3 years ago
9

345nm=____mmI need to see how to work the problem out​

Physics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

3.45×10⁻⁴mm (or 0.000345mm)

Explanation:

Use a method called dimensional analysis here. It involves a chain of conversions, so we'll need some conversions to work with.

  • 1nm = 1×10⁻⁹m
  • 1mm = 1×10⁻³m
  • 345nm; which is given

If you knew the conversion from nanometers to millimeters then you could just do it in one step. But I don't, so I won't. Anyways, you put the conversions into fraction form like so:

  • 1nm/1×10⁻⁹m
  • 1mm/1×10⁻³m

And then orient them in a way where multiplying the two (or more in other instances) gives you the units you want. In this cas it's millimeters so you'll have:

(345nm)•(1×10⁻⁹m/1nm)•(1mm/1×10⁻³m)

Notice how all the units reduce except for mm. From here you just multiply across and should get 345×10⁻⁶mm which simplifies to 3.45×10⁻⁴mm.

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An object traveling around another object in space is in what?
Gnoma [55]

Answer:

is called an orbit

Explanation:

a satellite is any natural or artificialobject that revolves around an object in space, just as the moon revolvesaround Earth.

8 0
3 years ago
Violet light of wavelength 405 nm ejects electrons with a maximum kinetic energy of 0.890 eV from a certain metal. What is the b
AleksandrR [38]

Answer:

  Ф = 2.179 eV

Explanation:

This exercise has electrons ejected from a metal, which is why it is an exercise on the photoelectric effect, which is explained assuming the existence of energy quanta called photons that behave like particles.

            E = K + Ф

the energy of the photons is given by the Planck relation

            E = h f

we substitute

           h f = K + Ф

           Ф= hf - K

the speed of light is related to wavelength and frequency

            c = λ f

            f = c /λ

            Φ = \frac{hc}{\lambda } - K

let's reduce the energy to the SI system

            K = 0.890 eV (1.6 10⁻¹⁹ J / 1eV) = 1.424 10⁻¹⁹ J

calculate

           Ф = 6.63 10⁻³⁴ 3 10⁸/405 10⁻⁹  -1.424 10⁻¹⁹

           Ф = 4.911 10⁻¹⁹ - 1.424 10⁻¹⁹

           Ф = 3.4571 10⁻¹⁹ J

         

we reduce to eV

           Ф = 3.4871 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

           Ф = 2.179 eV

4 0
3 years ago
Electromagnetic waves vary in
topjm [15]
The electromagnetic waves are types of waves which do not require medium for them to pass through to be able to travel from one location to another. The different types of electromagnetic waves therefore vary only in their wavelength and frequency. Thus, the answer is letter B. 
5 0
4 years ago
object carries a charge of -8.1 µC, while another carries a charge of -2.0 µC. How many electrons must be transferred from the
LenKa [72]

Number of electrons transferred: 1.91\cdot 10^{13}

Explanation:

The charge on the first object is

Q_1 = -8.1\mu C

while the charge on the 2nd object is

Q_2=-2.0 \mu C

When they are in contact, the final charge on each object will be

Q=\frac{Q_1+Q_2}{2}=\frac{-8.1+(-2.0)}{2}=-5.05 \mu C

So, the amount of charge (electrons) transferred from the 1st object to the 2nd object is

\Delta Q = Q_1 - Q = -8.1 -(5.05)=-3.05 \mu C = -3.05\cdot 10^{-6}C

The charge of one electron is

e=-1.6\cdot 10^{-19}C

Therefore, the number of electrons transferred is

N=\frac{Q}{e}=\frac{-3.05\cdot 10^{-6}}{-1.6\cdot 10^{-19}}=1.91\cdot 10^{13}

Learn more about electrons:

brainly.com/question/2757829

#LearnwithBrainly

8 0
3 years ago
What services do plants provide? Select the three that apply.
Irina18 [472]

The answer to this is B, C, and D. hope this helped

6 0
3 years ago
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