Answer:
the answer is debt
Step-by-step explanation:
To solve this equation there are many ways you can do to solve. One way is to simply substitute one variable for another.
5x = 5y - 25
X = y - 5
10y = 42 + 2x
10y = 42 + 2(y - 5)
10 y = 42 + 2y - 10
8y = 32
Y = 4.
X = y - 5
X = 4 - 5
X = -1.
P(X,y) = P(-1,4). This would be the solution or the point where they would intersect.
Answer:
![644,000,000\ cm^2](https://tex.z-dn.net/?f=644%2C000%2C000%5C%20cm%5E2)
Step-by-step explanation:
![We\ are\ given:\\Area\ of\ the\ map\ in\ m^2=64400\ m^2\\Hence,\ all\ we\ just\ have\ to\ do\ is\ to\ convert\ it\ into\ cm^2.\\Hence,\\Lets\ derive\ the\ formula\ of\ conversion\ from\ m^2\ to\ cm^2\ and\ vice\ versa.\\We\ know\ that,\\1m=100\ cm\\By\ squaring\ both\ the\ sides\ we\ get,\\(1m)^2=(100cm)^2\\Hence,\\1m^2=100^2\ cm^2\\1m^2=10,000\ cm^2\\Just\ in\ case\ you\ wanna\ convert\ cm^2\ to\ m^2,\\1m^2=10,000\ cm^2\\1cm^2=\frac{1}{10,000} m^2\\](https://tex.z-dn.net/?f=We%5C%20are%5C%20given%3A%5C%5CArea%5C%20of%5C%20the%5C%20map%5C%20in%5C%20m%5E2%3D64400%5C%20m%5E2%5C%5CHence%2C%5C%20all%5C%20we%5C%20just%5C%20have%5C%20to%5C%20do%5C%20is%5C%20to%5C%20convert%5C%20it%5C%20into%5C%20cm%5E2.%5C%5CHence%2C%5C%5CLets%5C%20derive%5C%20the%5C%20formula%5C%20of%5C%20conversion%5C%20from%5C%20m%5E2%5C%20to%5C%20cm%5E2%5C%20and%5C%20vice%5C%20versa.%5C%5CWe%5C%20know%5C%20that%2C%5C%5C1m%3D100%5C%20cm%5C%5CBy%5C%20squaring%5C%20both%5C%20the%5C%20sides%5C%20we%5C%20get%2C%5C%5C%281m%29%5E2%3D%28100cm%29%5E2%5C%5CHence%2C%5C%5C1m%5E2%3D100%5E2%5C%20cm%5E2%5C%5C1m%5E2%3D10%2C000%5C%20cm%5E2%5C%5CJust%5C%20in%5C%20case%5C%20you%5C%20wanna%5C%20convert%5C%20cm%5E2%5C%20to%5C%20m%5E2%2C%5C%5C1m%5E2%3D10%2C000%5C%20cm%5E2%5C%5C1cm%5E2%3D%5Cfrac%7B1%7D%7B10%2C000%7D%20m%5E2%5C%5C)
![Here,\\As\ the\ area\ of\ the\ field\ in\ m^2=64,400\ m^2\\ As\ the\ area\ of\ the\ field\ in\ cm^2=64,400\ m^2*10,000=644,000,000\ cm^2](https://tex.z-dn.net/?f=Here%2C%5C%5CAs%5C%20the%5C%20area%5C%20of%5C%20the%5C%20field%5C%20in%5C%20m%5E2%3D64%2C400%5C%20m%5E2%5C%5C%20As%5C%20the%5C%20area%5C%20of%5C%20the%5C%20field%5C%20in%5C%20cm%5E2%3D64%2C400%5C%20m%5E2%2A10%2C000%3D644%2C000%2C000%5C%20cm%5E2)
Think of numbers that when they are divided by 10, the remainder is 9.
So numbers like: 19, 29, 39, 49, 59, 69, 79, 89, and 99.
Now numbers that when they are divided by 9, the remainder is 8.
So numbers like: 17, 26, 35, 44, 53, 62, 71, 80, 89, and 98.
Now the number that is alike from the two sets of numbers is n.
n=89
Double check your work.
Divide 89 by 10. Remainder of 9
Divide 89 by 9. Remainder of 8.
Hope this helps :)