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3 years ago

Factorize 9/16 x2 + xy + 4/9 y2

1 answer:

7 0

$\frac{9}{16} x^2 + xy + \frac{4}{9} y^2 = (\frac{3}{4} x)^{2} + xy + (\frac{2}{3}y)^{2} = (\frac{3}{4} x)^{2} + 2* \frac{3}{4} x * \frac{2}{3}y + (\frac{2}{3}y)^{2}$ $= ( \frac{3}{4}x + \frac{2}{3} y)^{2}$

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For this case, the first thing you should know is that the opposite sides of the parallelogram are the same.

Therefore, we have the following equations:

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From equation 1 we have:

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Answer:

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$y = 9\\x = 3$

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3 years ago

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A fuel-tanker's tank is 50 feet long and has a diameter of seven feet. Determine the surface area of the fuel tank.

Bezzdna [24]

Answer:

1176.679ft²

Step-by-step explanation:

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S.A = 2 $\pi$ rh +2 $\pi$ r²

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3 years ago

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Activity 2

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The unknown is 2% and sorry

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3 years ago

What is the formula for a sphere?

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V=4/3 πr^3would be the formula

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A team of three students are working on a language-learning app; they need to develop 300 micro-lessons and 300 micro-tests befo

Olegator [25]

Answer: a) 15 b)

Step-by-step explanation:

Let X be the number of days:

For LESSONS:

Jordan does 10 / day ( 10*X)

Marco 5 / day ( 5*X)

Junyi 5 / day ( 5*X)

For TESTS:

Jordan does 5 / day ( 5*X)

Marco 10 / day ( 10*X)

Junyi 8 / day ( 8*X)

for each they need a total of 300

a) $10X+5X+5X=300 => 20X = 300 => X = 15$ days for the lessons

b) $5X+10X+8X = 300 => 23X = 300 => X = 13.04$ days for the tests

so they need 15 days to finish both tasks

now if Junyi gets sick we just eliminate his contribution

a) $10X+5X=300 => 15X = 300 => X = 20$ days for the lessons

b) $5X+10X = 300 => 15X = 300 => X = 20$ days for the tests

so in 20 days they will finish without him

If jordan works 10 hours a day, we just replace him with 10/24

a) $10(10/24)+5X+5X= 300 => X = 29.58$ days for the lessons

b) $5(10/24)+10X+8X = 300 => X = 16.51$ days for the tests

so at the end to complete both tasks they need 29.58 days

4 0

3 years ago