1. Average time for the first 0.25 m: 2.23 s
Explanation:
The average time that it takes for the car to travel the first 0.25 m is given by the average of the first three measures, so:
2. Average time to travel between 0.25 m and 0.50 m: 0.90 s
Explanation:
First of all, we need to calculate the time the car takes to travel between 0.25 m and 0.50 m for each trial:
t1 = 3.16 s - 2.24 s = 0.92 s
t2 = 3.08 s - 2.21 s = 0.87 s
t3 = 3.15 s - 2.23 s = 0.92 s
So, the average time is
3. Velocity in the second 0.25 m section: 0.28 m/s
Explanation:
The average velocity in the second 0.25 m section is equal to the ratio between the distance covered (0.25 m) and the average time taken (0.90 s):
Answer:
max height = 473.68 m
velocity hit mars = 60 m/s
Explanation:
Maximum height can be found by finding the 1st derivative of s(t) and equate it to zero.
s'(t) = ds/dt = 60 - 3.8t
s't() = 0
60 - 3.8t = 0
3.8t = 60
t = 60/3.8 = 15.79
subs t = 15.79 to s(t)
s(15.79) = 60(15.79) - 1.9(15.79)^2 = 473.68 m
b) The arrow will hit mars after it went up to the maximum height and travelled back downward due to gravity
Assuming the gravity constant, the velocity when it hit the ground should be the same as it leaves the ground. To confirm that, we tested with the equation of motion.
Since there is no gravity given, let a downward as g
v^2 = u^2 + 2as
The arrow shot upward will comes back downward. Since gravity is always constant, the time it took back to reach the ground should be the same as it goes up to max height
so, t = 2*15.79 = 31.58 s
s = 0 since we are looking at the moment it touches back the ground
v^2 = u^2 +2as
v^2 = 60^2 + 2g(0)
v^2 = 60^2
v = 60 m/s
Answer:
d = 4.47 [m]
Explanation:
To solve this problem we must make a free body diagram, where we can see the direction of the force acting with the appropriate angles. In the attached image we can see the free body diagram mentioned.
So in the image, we can see an angle of 65° with respect to the horizontal, therefore we can calculate the horizontal component of the force.
Fx = 22.4*cos (65)
Fx = - 9.46 [N] (it's negative because the force is pointing in the negative direction).
We can obtain the same result using 115° as the angle.
Fx = 22.4*cos (115)
Fx = 9.46 [N]
Now we know that work is defined as the product of the force by the distance, therefore we have.
Note: Always the work must be calculated with the force parallel
to the movement
W = F*d
Where:
W = work = 42.3 [J] (units of joules)
F = force parallel to the movement = 9.46 [N]
d = distance [m]
d = W/F
d = 42.3/9.46
d = 4.47 [m]
Answer:
cryosphere is all those areas of earth where the surface is frozen while hydrosphere is all waters of earth, as distinguished from the land and the gasses of the atmosphere
The net force is determined is basically who is pushing harder in a specific direction.Like since there bith pushing in the same direction the net force is in the direction that they are pushing.