Answer:
(a) F = 320
(b) = F = -5.1625
Explanation:
The formula that converts degree Celsius (C) to degree Fahrenheit (F) is:
F = 1.8C + 32
Solving (a): F = 2C
Substitute 2C for F in the above equation
F = 1.8C + 32
2C = 1.8C + 32
Collect like terms
2C - 1.8C = 32
0.2C = 32
Multiply both sides by 5
5 * 0.2C = 32 * 5
C = 160
Recall that F = 2C
F = 2 * 160
F = 320
Solving (b): F = ¼C
Substitute ¼C for F in the above formula
F = 1.8C + 32
¼C = 1.8C + 32
Convert fraction to decimal
0.25C = 1.8C + 32
Collect like terms
0.25C - 1.8C = 32
-1.55C = 32
Divide both sides by -1.55
C = 32/(-1.55)
C = -32/1.55
C = -20.65
Recall that: F = ¼C
F = -¼ * 20.65
F = -5.1625
Engines can overheat for many reasons. In general, it's because something's wrong within the cooling system and heat isn't able to escape the engine compartment. The source of the issue could include a cooling system leak, faulty radiator fan, broken water pump, or clogged coolant hose.
Hope it helps! Have a nice day or night!
Answer
Voltage is how fast the electrons flow. Power is a use of voltage times the volumes of electrons. The higher the voltage the more power you have with the same current.
Answer:
Approximately
.
Assumption: the ball dropped with no initial velocity, and that the air resistance on this ball is negligible.
Explanation:
Assume the air resistance on the ball is negligible. Because of gravity, the ball should accelerate downwards at a constant
near the surface of the earth.
For an object that is accelerating constantly,
,
where
is the initial velocity of the object,
is the final velocity of the object.
is its acceleration, and
is its displacement.
In this case,
is the same as the change in the ball's height:
. By assumption, this ball was dropped with no initial velocity. As a result,
. Since the ball is accelerating due to gravity,
.
.
In this case,
would be the velocity of the ball just before it hits the ground. Solve for
.
.
Answer: 
Explanation:
This problem can be solved by the following equation:

Where:
is the change in kinetic energy
is the electric potential difference
is the electric charge
Finding
:


Finally:
