Answer:
Following are the answer to this question:
Explanation:
In option (a):
- The principle of Snells informs us that as light travels from the less dense medium to a denser layer, like water to air or a thinner layer of the air to the thicker ones, it bent to usual — an abstract feature that would be on the surface of all objects. Mostly, on the contrary, glow shifts from a denser with a less dense medium. This angle between both the usual and the light conditions rays is referred to as the refractive angle.
- Throughout in scenario, the light from its stars in the upper orbit, the surface area of both the Earth tends to increase because as light flows from the outer atmosphere towards the Earth, it defined above, to a lesser angle.
In option (b):
- Rays of light, that go directly down wouldn't bend, whilst also sun source which joins the upper orbit was reflected light from either a thicker distance and flex to the usual, following roughly the direction of the curve of the earth.
- Throughout the zenith specific position earlier in this thread, astronomical bodies appear throughout the right position while those close to a horizon seem to have been brightest than any of those close to the sky, and please find the attachment of the diagram.
The answer is evolution. When a specifies evolves over time they change and adapt to their environment.
Answer:
Ionic compound.
Explanation:
812° C is a very high melting point. Such high melting points are generally ionic compound. Ionic compounds are have very strong bond between the elements ( electrostatic bond). In order to break this bond, large amount of heat energies are needed. So, they have high melting point. Also, Ionic compound are very good conductors of electricity.
Answer:
a) v = 1.075*10^7 m/s
b) FB = 7.57*10^-12 N
c) r = 10.1 cm
Explanation:
(a) To find the speed of the alpha particle you use the following formula for the kinetic energy:
(1)
q: charge of the particle = 2e = 2(1.6*10^-19 C) = 3.2*10^-19 C
V: potential difference = 1.2*10^6 V
You replace the values of the parameters in the equation (1):
![K=(3.2*10^{-19}C)(1.2*10^6V)=3.84*10^{-13}J](https://tex.z-dn.net/?f=K%3D%283.2%2A10%5E%7B-19%7DC%29%281.2%2A10%5E6V%29%3D3.84%2A10%5E%7B-13%7DJ)
The kinetic energy of the particle is also:
(2)
m: mass of the particle = 6.64*10^⁻27 kg
You solve the last equation for v:
![v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.84*10^{-13}J)}{6.64*10^{-27}kg}}\\\\v=1.075*10^7\frac{m}{s}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7B2K%7D%7Bm%7D%7D%3D%5Csqrt%7B%5Cfrac%7B2%283.84%2A10%5E%7B-13%7DJ%29%7D%7B6.64%2A10%5E%7B-27%7Dkg%7D%7D%5C%5C%5C%5Cv%3D1.075%2A10%5E7%5Cfrac%7Bm%7D%7Bs%7D)
the sped of the alpha particle is 1.075*10^6 m/s
b) The magnetic force on the particle is given by:
![|F_B|=qvBsin(\theta)](https://tex.z-dn.net/?f=%7CF_B%7C%3DqvBsin%28%5Ctheta%29)
B: magnitude of the magnetic field = 2.2 T
The direction of the motion of the particle is perpendicular to the direction of the magnetic field. Then sinθ = 1
![|F_B|=(3.2*10^{-19}C)(1.075*10^6m/s)(2.2T)=7.57*10^{-12}N](https://tex.z-dn.net/?f=%7CF_B%7C%3D%283.2%2A10%5E%7B-19%7DC%29%281.075%2A10%5E6m%2Fs%29%282.2T%29%3D7.57%2A10%5E%7B-12%7DN)
the force exerted by the magnetic field on the particle is 7.57*10^-12 N
c) The particle describes a circumference with a radius given by:
![r=\frac{mv}{qB}=\frac{(6.64*10^{-27}kg)(1.075*10^7m/s)}{(3.2*10^{-19}C)(2.2T)}\\\\r=0.101m=10.1cm](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bmv%7D%7BqB%7D%3D%5Cfrac%7B%286.64%2A10%5E%7B-27%7Dkg%29%281.075%2A10%5E7m%2Fs%29%7D%7B%283.2%2A10%5E%7B-19%7DC%29%282.2T%29%7D%5C%5C%5C%5Cr%3D0.101m%3D10.1cm)
the radius of the trajectory of the electron is 10.1 cm