The answer would be 10 because if u put abcde over fghij, hi and cd are the same place so its the same answer or a mulitple of 10
The picture is not clear. let me assume
y = (x^4)ln(x^3)
product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)
dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)
look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)
end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]
90ft by 7ft gives an area of:
90 x 7 = 630 sq ft
1/2 fl oz is needed for each square foot
630 x 1/2 = 315 fl oz required.
Answer:
y = 14/5x + 2
Step-by-step explanation:
is seems as though the y-intercept would be 2 and the slope is 2.8 which is
2 4/5 or 14/5
therefore, equation would be y = 14/5x + 2
Answer:
L=1 ft and B=84 ft
L=2 ft and B=42 ft
L=4ft and B=21ft
L=6ft and B=14 ft
L=7ft and B=12ft
L=12 ft and B=7ft
L=14ft and B=6 ft
L=21 ft and B=4 ft
L=42 ft and B=2 ft
L=84 ft and B=1 ft
Step-by-step explanation:
We are given that
Area of rectangular floor=84 square feet
We have to find the possible length and width of for Angelo's clubhouse.
Area of rectangle=
Using the formula
Area of rectangular floor for clubhouse=84 square feet

Factor of 84 are
1,2,4,6,7,12,14,21,42,84
Therefore, possible dimension of rectangular floor

L=1 ft and B=84 ft
L=2 ft and B=42 ft
L=4ft and B=21ft
L=6ft and B=14 ft
L=7ft and B=12ft
L=12 ft and B=7ft
L=14ft and B=6 ft
L=21 ft and B=4 ft
L=42 ft and B=2 ft
L=84 ft and B=1 ft