How do you interpret algebraic expressions in terms of their context

2 answers:

8 0

Interpret expressions that represent a quantity in terms of its context. Interpret parts of an, such as terms, factors, and coefficients.

NNADVOKAT [17]3 years ago

6 0

Well, it really depends on the context they are in. For instance,
$2x^2 + 3x$ is different than $2xyt + 3xy + 2xyt$ or
$y = 2x + 5$ or $2x^3 + 2x^2 + 4x + 4$ They all are interpret differently. For instance, one is a line, another is a square and one is a cube.

You might be interested in

The price for a car in 2015 was RM 54000. This was 10% higher compared to the year 2014?

-Dominant- [34]

Answer:

2014 price was $49,091

Step-by-step explanation:

I'm assuming you want to solve for 2014 year price...

2015 year price is 54,000 and was 10% higher than 2014 price, meaning 2015 price is 110% of 2014 price so...

p×110%=54,000

p=54,000/1.1

p=49,090.90

5 0

3 years ago

10. the quotient is 58 and the remainder is 3. What is the number

KiRa [710]

Answer:

Step-by-step explanation: 58 - 3 = 55.

3 0

2 years ago

HELP PLEASE !!!!!!!!!!

Arada [10]

Answer:

Answer B $(-\infty,1)U(1,2]$

Step-by-step explanation:

Notice that the quotient of f(x)/g(x) is:

$h(x)=\frac{\sqrt{2-x} }{x-1}$

therefore, this new function imposes conditions due to the fact that it has a square root in the numerator and a binomial in the denominator both with the variable x. Then, in order for the root in the numerator to be defined, the argument inside the root must be larger than or equal to zero. That is:

$2-x\geq 0\\2\geq x\\x\leq 2$

So, this condition must be satisfied by the x-values of the domain.

Then we have the binomial in the denominator, which in order to be defined needs to be different from zero. Notice that the only x-value that could cause problems (render zero) is:

$x-1=0\\x=1$