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3 years ago

How do you interpret algebraic expressions in terms of their context

2 answers:

8 0

Interpret expressions that represent a quantity in terms of its context. Interpret parts of an, such as terms, factors, and coefficients.

NNADVOKAT [17]3 years ago

6 0

Well, it really depends on the context they are in. For instance,
$2x^2 + 3x$ is different than $2xyt + 3xy + 2xyt$ or
$y = 2x + 5$ or $2x^3 + 2x^2 + 4x + 4$ They all are interpret differently. For instance, one is a line, another is a square and one is a cube.

You might be interested in

Divide (6x3y2 + 12x2y - 8xy) by (2xy)

rosijanka [135]

Answer:

Step-by-step explanation:

6x³y² = 2 * 3 * x³ * y²

12x²y = 2 *3 * 2 * x² * y

8xy = 2 * 2 * 2 *x * y

GCF = 2xy

6x³y² + 12x²y - 8xy = (2xy * 3x²y) + (2xy * 6x) - (2xy * 4)

= 2xy *(3x²y + 6x - 4)

$\dfrac{6x^{3}y^{2}+12x^{2}y-8xy}{2xy}=\dfrac{2xy*(3x^{2}y+6x-4)}{2xy}\\\\\\= 3x^{2}y + 6x - 4$

5 0

2 years ago

Anthony read 5 6 hour each day for 5 days. as an equation

ivanzaharov [21]

Answer: 56x÷5=?

Step-by-step explanation:11.2 hours a day

6 0

2 years ago

Given the function f(x)=-3x^3+9x^2-2x+3 what part of the function indicates that the left end starts at the top of the graph

lina2011 [118]

Given the function f(x)=-3x^3+9x^2-2x+3 what part of the function indicates that the left end starts at the top of the graph

The negative sign in the cubed term.

3 0

3 years ago

9 hundred equals how many tens

user100 [1]

Answer:

90 tens

Step-by-step explanation:

We know that there are 10 tens in a hundred, so this will be our unit rate for the rest of this problem. Since we have 9 hundreds, we have to multiply by 10 to get our answer.

9 × 10 = 90

The answer to our question is 90 tens are in 9 hundreds.

3 0

3 years ago

'Polonium-210 is a radioactive substance with a half-life of 138 days. If a nuclear

Tatiana [17]

Answer:

<u>59.0891 g (rounded to 4 decimal places)</u>

Explanation:

<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.

Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:

$A=A_0\cdot (1/2)^n$

Where:

A is the amount that remains of the substance after n half-lives have elapses, and

A₀ is the starting amount of the substance.

In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:

330 days / 138 days = 2.3913

Therefore, the amount of polonium-210 that will be left in 330 days is:

$A=310{g}\cdot (1/2)^{2.3913}=59.0891g$

5 0

2 years ago