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2 years ago

2. The amount paid for different weights of oranges at a farmer’s market are shown below.

1 answer:

7 0

She could have taken the price and number of pounds and divided the price by two until she had the price for one of oranges. that is all i know, i hope it helps.

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I NEED URGENT ASSISTANCE

Nata [24]

Answer:

8 C sometimes

9 64x^8 y^11

10 c 1.28r^2/ t^9

Step-by-step explanation:

Algebraic Operations

Some basic rules must be fresh in our minds when trying to simplify complex algebraic expressions. For example, the power rule respect to the product or quotient:

$\displaystyle \left(\frac{x^n.y^m}{z^p}\right)^q= \frac{x^{qn}.y^{qm}}{z^{qp}}$

$\displaystyle \frac{x^n.x^q}{x^p}= x^{n+q-p}$

$\displaystyle x^{-n}=\frac{1}{x^n}$

Let's face the questions at hand

8. A number is raised to a negative exponent is negative?

Following the expressions recalled above, let's pick the expression

$\displaystyle 3^{-2}=\frac{1}{3^2}=\frac{1}{9}$

This is a negative power resulting in a positive number

Now we pick

$\displaystyle (-2)^{-3}=\frac{1}{(-2)^3}=-\frac{1}{8}$

This time, the negative power leads to a negative result, so it doesn't matter the sign of exponent to determine the sign of the result

Answer: C sometimes

9 simplify(4xy^2)^3(xy)^5

$(4xy^2)^3(xy)^5=4^3x^3(y^2)^3x^5y^5$

$=64x^3y^6x^5y^5$

$=64x^8y^{11}$

10 simplify(2t^-3)^3(0.4r)^2

$(2t^{-3})^3(0.4r)^2=2^3(t^{-3})^30.4^2r^2$

$=8t^{-9} 0.16 r^2$

$=1.28t^{-9} r^2$

$\displaystyle \frac{1.28 r^2}{t^9}$

7 0

3 years ago

PLEASE ANSWER...I WILL MARK WHOEVER ANSWERS FIRST BRAINLIEST!!!

klemol [59]

Answer:

32 is 40% of 80

Step-by-step explanation:

i just asked my alexa lol ._.

6 0

3 years ago

the graph of y= 1/x is translated 3 units up and 2 units to the left. what is an equation of the translated graph

wel

-Move 2 units left:y=(1/x +2)
-Move 3 units up:y= (1/x +2)+3
So the equation is y= (1/x +2)+3

8 0

2 years ago

A market research team compiled the following discrete probability distribution, where X represents the number of automobiles ow

rodikova [14]

Answer:

The standard deviation of X is 0.7

Step-by-step explanation:

We are given the following distribution:

x: 0 1 2 3

P(x): 0.3 0.5 0.2 0.4

We have to find the standard deviation of X.

Formula:

$E(x) = \displaystyle\sum x_iP(x_i)\\\\E(x) =0(0.3) + 1(0.5) + 2(0.2) + 3(0.4)\\\\E(x) = 2.1\\\\E(x^2) = \displaystyle\sum x_i^2P(x_i)\\\\E(x^2) =0(0.3) + 1(0.5) + 4(0.2) + 9(0.4)\\\\E(x^2) = 4.9\\\\Var(x) = E(x^2) - (E(x))^2 = 4.9-(2.1)^2 = 0.49\\\\\sigma(x) = \sqrt{Var(x)} =\sqrt{0.49} = 0.7$

Thus, the standard deviation of X is 0.7

6 0

3 years ago

Simplify: -0.8b + 4.1c -(-3.2b) - 0.1c

umka21 [38]

-0.8b+4.1c-(-3.2b)-0.1c
-(-3.2b)= 3.2b
4.1c-0.1c=4c
-0.8b+4c+3.2b
-0.8b+3.2b=2.4b

4c+2.4b

3 0

2 years ago

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