Answer:
, 6.1 s
Explanation:
The motion of the dropped penny is a uniformly accelerated motion, with constant acceleration
towards the ground. If the penny is dropped from a height of
the vertical position of the penny at time t is given by the equation
where the negative sign is due to the fact that the direction of the acceleration is downward.
We want to know the time t at which the penny reaches the ground, which means h(t)=0. Substituting into the equation, it becomes
And re-arranging it, we find an expression for the time t:
And substituting the numbers, we can also find the numerical value:
Answer:
Q= 6213.72 J
Explanation:
Given that
n = 2.2 moles
T= 490 K
Given that gas is ideal gas and process is isothermal.
We know that internal energy for ideal gas only depends on the temperature.The temperature change in the isothermal process is zero.That is why internal energy change will be zero.
ΔU = 0
From first law of thermodynamics
Q = ΔU + W
Q= W
We know that work for isothermal process
Given that V₂ = 2 V₁
R=gas constant = 0.0821 atm.L/K.mol
W= 2.2 x 0.0821 x 490 ln2 atm.L
W=61.34 atm.L
W=Q= 61.34 atm.L
We know that
1 atm.L = 101.3 J
Q= 6213.72 J
I.The vector sum of the three forces must equal zero.
Explanation:
An object is said in translational equilibrium when it is moving at constant velocity (note that the velocity can also be zero, so an object at rest is also in translational equilibrium).
Since the velocity is constant, this also means that the acceleration of the object is zero:
According to Newton's second law, the net force on an object is equal to the product between its mass and its acceleration:
where
is the vector sum of the forces acting on the object
m is the mass of the object
a is its acceleration
For an object in translational equilibrium, , and therefore
Applied to this case, this means that
I.The vector sum of the three forces must equal zero.
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A.the universal gravitational law
is the integrals for the magnitude of the electric field.
A characteristic of electricity exists at every location in space when charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.
The formula for the electric field due to a point charge is:
Here q is the charge, r is the distance from the charge, and k = 8.99 ×
Imagine an infinitely - tiny portion of this charge distribution that has a charge . This charge produces an electric field dE with magnitude:
Here, λ = 3.0 nC/m dq
= λ.dy dE = ∫k.dq
From y = -3 m to y = 2 m, there is a 3.0 nC/m uniform linear charge distributed along the y axis.
The integrals for the magnitude of the electric field at y = 4 m on the y axis:
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